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Free Force and Motion MCQs with Answers

1,416 Force and Motion MCQs from Physics, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.

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Displacement and VelocityAccelerationProjectile MotionNewton's Laws of MotionLinear MomentumCollisions
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1,416 questions · page 52 of 71

1021. A two-car train, with data as given in Fig. is pulled by a child on a horizontal frictionless surface. The strings are massless. The force exerted by car A on the string S is:

  • A. 10N
  • B. 20N
  • C. Zero
  • D. 15N

Explanation: To solve this problem, use Newton's second law, F = ma. First, find the total mass of the two-car system.

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Correct answer: 15N

1022. An object is projected upwards with a velocity of 100 m/s. It will strike the ground after (approximately)

  • A. 10 sec
  • B. 15 sec
  • C. 20 sec
  • D. 5 sec

Explanation: To determine the total time of flight for an object projected upwards with an initial velocity, you can use the first equation of motion…

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Correct answer: 20 sec

1023. When force of 1 N is applied on a body of mass 100 g then the acceleration would be

  • A. 5 m s-2
  • B. 10 m s-2
  • C. 0.5 m s-2
  • D. 0.1 m s-2

Explanation: To find the acceleration, use Newton's second law, which states that Force = Mass × Acceleration (F = ma).

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Correct answer: 10 m s-2

1024. A mass of 10 kg moves with an acceleration of 10 m s-2, the force on it is

  • A. 5 N
  • B. 50 N
  • C. 100 N
  • D. 25 N

Explanation: To determine the force exerted on the object, apply Newton's Second Law of Motion, which states that the force (F) is the product of mass…

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Correct answer: 100 N

1025. The average force necessary to stop a hammer with 25 N s momentum in 0.05 s expressed in 'N' is

  • A. 500
  • B. 50
  • C. 125
  • D. 25

Explanation: Change in momentum = Applied force x Elapsed Time ΔP= F x t Making force the subject; F= ΔP/t = 25/0.05=500N

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Correct answer: 500

1026. A projectile can have the same range R for two angles of projection. If t1 and t2 are the times of nights in the two cases, then product of the time of flights is proportional to:

  • A. R2
  • B. 1/R2
  • C. 1/R
  • D. R

Explanation: For a projectile launched with identical speeds, the range R is the same for two complementary angles θ and (90° - θ).

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Correct answer: R

1027. A cricket ball of mass 0.5 kg strikes a bat normally with a velocity of 30 m s-1 and rebounds with a velocity of 20 ms-1 in the opposite direction. The impulse of the force exerted by the ball on the bat is

  • A. 0.5 N s
  • B. 25 N s
  • C. 1.0 N s
  • D. 50 N s

Explanation: Impulse is defined as the change in momentum of an object. For this problem, you calculate the impulse by finding the change in velocity…

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Correct answer: 25 N s

1028. A small submarine of mass 1000 kg sinks in water with a uniform speed of 2 m/s. What is the resultant force exerted on the submarine as it sinks?

  • A. 0 N
  • B. 500 N
  • C. 2000 N
  • D. 10000 N

Explanation: When an object moves with a uniform speed, it implies there is no acceleration.

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Correct answer: 0 N

1029. A handball is tossed vertically upward with a velocity of 19.6 meters per second. Approximately how high will it rise?

  • A. 15 m
  • B. 25 m
  • C. 20 m
  • D. 30 m

Explanation: The correct answer is 20 m. The maximum height of a projectile thrown vertically upward can be found using the formula h = (vi2) / (2g).

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Correct answer: 20 m

1030. Time taken by a projectile to reach maximum height is t =

  • A. Option A
  • B. Option B
  • C. Option C
  • D. Option D

Explanation: Formula in option C is used to calculate the time taken for a projectile to reach maximum height.

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Correct answer: Option C

1031. A stone is thrown horizontally with an initial speed 30 m/s from a bridge. Find the stone's total speed when it enters the water4 s later. (Ignore air resistance.)

  • A. 30 m/s
  • B. 40 m/s
  • C. 50 m/s
  • D. 60 m/s

Explanation: The stone is thrown with an initial horizontal velocity of 30 m/s, so the horizontal component of its velocity remains constant at 30 m/s…

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Correct answer: 50 m/s

1032. A force F = 8i -6j -10k newton produces acceleration of 1 m s-2 in a body. The mass of the body is:

  • A. 10kg
  • B. 10√2kg
  • C. 10√3kg
  • D. 200kg

Explanation: To solve the problem, first calculate the magnitude of the force vector F = 8i - 6j - 10k.

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Correct answer: 10√2kg

1033. A force of 6 N acts on a mass of 1 kg which acquires a velocity 30 ms-1. The time for which the force acts is

  • A. 26 s
  • B. 6 s
  • C. 5s
  • D. 2 s

Explanation: The problem involves calculating the time during which a force acts on an object.

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Correct answer: 5s

1034. A wooden block of mass 0.60 kg is on a rough horizontal surface. A force of 12 N is applied to the block and it accelerates at 4.0 ms-2. What is the magnitude of the frictional force acting on the block?

  • A. 2.4 N
  • B. 9.6 N
  • C. 14 N
  • D. 16 N

Explanation: According to Newton's 2nd law of motion:Net force = maForward force - frictional force = ma12 - frictional force = 0.60 x 4frictional…

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Correct answer: 9.6 N

1035. A force of 5 newton acts on a body of weight 9.80 newton. What is the acceleration produced in m s-2?

  • A. 0.51
  • B. 1.96
  • C. 5.00
  • D. 49.00

Explanation: To determine the acceleration, apply Newton's second law: F = ma. Start by calculating the body's mass from its weight: W = mg, where g =…

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Correct answer: 5.00

1036. A body moves from point P(3, 4) to Q(5, 7). Its displacement vector would be:

  • A. Option A
  • B. Option B
  • C. Option C
  • D. Option D

Explanation: The following is the solution: Position vector P = OP = 3i + 4j Position Vector Q = OQ = 5i + 7j Displacement vector = PQ = OQ - OP PQ =…

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Correct answer: Option D

1037. The speed of the cyclist between two points S1 and S2 as shown in figure is:

  • A. 10 km h-1
  • B. 20 k/m h-1
  • C. 30 km h-1
  • D. 50 km h-1

Explanation: The following is the solution: The cyclist travels a total distance of 20 km, but they do it in 20 minutes, not 1 hour.

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Correct answer: 30 km h-1

1038. What is the acceleration produced by a force of 0.5N applied on a body of mass 0.1 kg?

  • A. 0.1 ms-2
  • B. 0.5 ms-2
  • C. 1 ms-2
  • D. 5 ms-2

Explanation: To determine the acceleration, use Newton's Second Law of Motion, which states F = ma.

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Correct answer: 5 ms-2

1039. Impulse has always changed:

  • A. Energy
  • B. Momentum
  • C. Velocity
  • D. Acceleration

Explanation: Impulse is defined as the change in momentum of an object when a force is applied over a period of time.

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Correct answer: Momentum

1040. A ball is thrown vertically upwards at 19.6 m/s. For its complete trip (up and back down to the starting position), its average speed is:

  • A. 19.6 m/s
  • B. 9.8 m/s
  • C. 6.5 m/s
  • D. 4.9 m/s

Explanation: The following is the solution: We are first going to find time using the formula: v = u + at where: v = final velocity (zero at the…

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Correct answer: 9.8 m/s
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