A wooden block of mass 0.60 kg is on a rough horizontal surface. A force of 12 N is applied to the block and it accelerates at 4.0 ms-2. What is the magnitude of the frictional force acting on the block?
Correct answer: B. 9.6 N
- A. 2.4 N
- B. 9.6 N
- C. 14 N
- D. 16 N
Explanation
According to Newton's 2nd law of motion:Net force = maForward force - frictional force = ma12 - frictional force = 0.60 x 4frictional force = 12 - 2.4frictional force = 9.6 N
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