A force of 6 N acts on a mass of 1 kg which acquires a velocity 30 ms-1. The time for which the force acts is
Correct answer: C. 5s
- A. 26 s
- B. 6 s
- C. 5s
- D. 2 s
Explanation
The problem involves calculating the time during which a force acts on an object. The formula used is F = mΔv / Δt, where F is the force, m is the mass, Δv is the change in velocity, and Δt is the change in time. Given: F = 6 N, m = 1 kg, and Δv = 30 m/s, we rearrange the formula to find Δt: Δt = mΔv / F = (1 kg × 30 m/s) / 6 N = 5 s. Options A, B, and D represent incorrect calculations and do not apply the relationship correctly, leading to incorrect time values.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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