A force of 6 N acts on a mass of 1 kg which acquires a velocity 30 ms-1. The time for which the force acts is
Correct answer: C. 5s
- A. 26 s
- B. 6 s
- C. 5s
- D. 2 s
Explanation
The problem involves calculating the time during which a force acts on an object. The formula used is F = mΔv / Δt, where F is the force, m is the mass, Δv is the change in velocity, and Δt is the change in time. Given: F = 6 N, m = 1 kg, and Δv = 30 m/s, we rearrange the formula to find Δt: Δt = mΔv / F = (1 kg × 30 m/s) / 6 N = 5 s. Options A, B, and D represent incorrect calculations and do not apply the relationship correctly, leading to incorrect time values.
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