A handball is tossed vertically upward with a velocity of 19.6 meters per second. Approximately how high will it rise?
Correct answer: C. 20 m
- A. 15 m
- B. 25 m
- C. 20 m
- D. 30 m
Explanation
The correct answer is 20 m. The maximum height of a projectile thrown vertically upward can be found using the formula h = (vi2) / (2g). Here, vi is 19.6 m/s (initial velocity) and g is 9.8 m/s2 (acceleration due to gravity). Substituting these values, we have h = (19.6)2 / (2 × 9.8) = 384.16 / 19.6 = 19.6 m, which rounds to 20 m. Option A (15 m) underestimates this value, Option B (25 m) and Option D (30 m) overestimate it. Only Option C matches the calculated height of approximately 20 m.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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