A projectile can have the same range R for two angles of projection. If t1 and t2 are the times of nights in the two cases, then product of the time of flights is proportional to:
Correct answer: D. R
- A. R2
- B. 1/R2
- C. 1/R
- D. R
Explanation
For a projectile launched with identical speeds, the range R is the same for two complementary angles θ and (90° - θ). The time of flight for each angle, t1 and t2, results in a product that is proportional to the range R. This is because the time of flight is determined by the vertical component of the initial velocity, and their product yields a direct relationship with the horizontal range. Therefore, option D is correct: R. The other options incorrectly assume different forms of dependency that do not apply to the physics of projectile motion.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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