Free Capacitors MCQs with Answers
63 Capacitors MCQs from Physics, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Capacitors store electric charge and energy in an electric field between conductors. Work includes capacitance, the relation Q = CV, dielectric materials, charging and discharging, energy formulas, and combinations of capacitors in series and parallel. Electric potential difference is needed to understand why charge and stored energy change.
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63 questions · page 3 of 4
- A. Potential difference
- B. Gravitational force
- C. Charge magnitude
- D. Capacitance
- E. None of these
Explanation: The explanation for this question will be added soon.
Correct answer: Potential difference- A. 8 μF
- B. 3/2 μF
- C. 4 μF
- D. 13/2 μF
Explanation: If two capacitors of capacitance 2 μF and 6 μF are connected in parallel, the equivalent capacitance of combination will be the direct sum.
Correct answer: 8 μF- A. Distance between plates
- B. Separation between plates
- C. Medium
- D. Metal of plates
Explanation: Capacitance of a capacitor does not depend upon metal of plates.
Correct answer: Metal of plates- A. E = ½ cv2
- B. E.2cv2
- C. E.cv2
- D. None of these
Explanation: The energy stored in a capacitor can be expressed in three ways: E=((CV)2)/2 where Q is the charge, V is the voltage, and C is the…
Correct answer: E = ½ cv2- A. Capacitor
- B. Conductor
- C. Inductor
- D. Generator
Explanation: The energy stored between the plates of a charged capacitor is electrical potential energy.
Correct answer: Capacitor- A. C1 + C2
- B. 1/C1 + C2
- C. C1C2/C1 + C2
- D. 2C1C2 /C1 + C2
Explanation: When capacitors are connected in parallel, their equivalent capacitance is simply the sum of the individual capacitances.
Correct answer: C1 + C2- A. Coulomb
- B. Volt
- C. Farad
- D. Ampere
Explanation: Capacitance is measured in Farads (F) in the International System of Units (SI).
Correct answer: Farad48. While studying charging and discharging of a capacitor, Rc = Resistance x Capacitance is known as?
- A. Electrostatic constant
- B. Time constant
- C. Dielectric constant
- D. Proportionality constant
Explanation: In the context of charging and discharging a capacitor, the term "Re" stands for the time constant of the circuit, which is calculated by…
Correct answer: Time constant- A. The capacitance falls to half its initial value, and the charge remains the same
- B. Th capacitance and the charge both fall to half their initial values
- C. The capacitance and the charge both double
- D. The capacitance remains the same, and the charge doubles
Explanation: Since the capacitor an its nature is not changed, the capacitance must remain constant.
Correct answer: The capacitance remains the same, and the charge doubles50. Resistance in RC circuit of time constant 2 seconds is 1000 Ohms. What is value Of C in the circuit?
- A. 2 u farad.
- B. 20 u farad
- C. 200 u farad
- D. 2000 u farad
Explanation: An RC time constant is given by,t=R×C.Given that,t=2 secondR= 1000 Ohms then,2=1000 x CC = 2/1000C= 0.002C = 2 x 10-3 FC = 2 x 10-3 /…
Correct answer: 2000 u farad- A. Double
- B. Half
- C. Four-times
- D. Eight-times
Explanation: The capacitance of a parallel plate capacitor is given by C = A/D Where ε is the permittivity of the dielectric, A is the area of the…
Correct answer: Double52. Which one of the following must be decreased in order to increase the capacitance of a capacitor?
- A. The area of the plates
- B. The distance between the plates
- C. The number of the plates
- D. The dielectric constant
Explanation: The formula for capacitance is C = εo εr A/d. Decreasing the distance between the plates would increase the capacitance since C is…
Correct answer: The distance between the plates- A. 6 volt
- B. 1 volt
- C. 3 volt
- D. 2 volt
Explanation: When capacitors are connected in series, the total capacitance (C_total) is given by the reciprocal of the sum of the reciprocals of the…
Correct answer: 6 volt- A. Relative permittivity
- B. Permittivity
- C. Permeability
- D. Electric polarization
Explanation: The ratio of the capacitance of the capacitor with a dielectric to the capacitance of the same capacitor with free space is given by the…
Correct answer: Relative permittivity- A. 1/2 CV2
- B. 1/2 QV
- C. 1/2 m v2
- D. Both A and B
Explanation: The correct answer is Option D: Both A and B. The energy stored in a charged capacitor can be represented by the formulas E = 1/2 CV² or E…
Correct answer: Both A and B- A. Be fully charged in 1 second by a current of 1 Ampere
- B. Store 1 coulomb of charge at potential difference of 1 volt
- C. Gain 1 joule of energy when 1 coulomb of charge is stored on it
- D. Discharge in 1 second when connected across a resistor of resistance 3 ohms
Explanation: A capacitance of 1F produces 1V of potential difference for an electric charge of one coulomb (1C).
Correct answer: Store 1 coulomb of charge at potential difference of 1 volt- A. E√10
- B. E/√10
- C. 10E
- D. E/10
Explanation: The relationship between the electric field in the absence of the dielectric (E0) and the electric field with the dielectric (E) is given…
Correct answer: E/10- A. 4x
- B. 2x
- C. x/2
- D. x/4
Explanation: C = A𝛆 / d where C is capacitance, 𝛆 is the permittivity of free space, A is the area of plates, and d is the distance between them.
Correct answer: x/2- A. 400 J
- B. 4 J
- C. 0.2 J
- D. 200 J
Explanation: The energy stored in a capacitor can be calculated using the formula U = 0.5 * Q * V, where U is the energy, Q is the charge, and V is the…
Correct answer: 200 J- A. 2 F
- B. 4 F
- C. 0.5 F
- D. 0.25 F
Explanation: The potential difference across the parallel plate capacitor is 10V- (-10)=20VCapacitance= Q/V = 40/20 = 2 FaradAs it is numerical, it can…
Correct answer: 2 F