The electric field between the plates of an isolated air-spaced parallel- plate capacitor is E. What is the field between the plates after immersing the capacitor in a liquid of relative permitivity 10?
Correct answer: D. E/10
- A. E√10
- B. E/√10
- C. 10E
- D. E/10
Explanation
The relationship between the electric field in the absence of the dielectric (E0) and the electric field with the dielectric (E) is given by:E = E0 / εrwhere εr is the relative permittivity of the medium.In this case, the relative permittivity of the liquid is given as 10. Therefore, the fiel used between the plates after immersing the capacitor in the liquid is:E' = E / εr = E / 10So, the correct answer is option 4E / 10SO, ELECTRIC FIELD WILL DECREASE BY A FACTOR 10.
This question appeared on the ETEA MDCAT 2014 paper, which you can sit online with every answer explained.
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About Capacitors
Capacitors store electric charge and energy in an electric field between conductors. Work includes capacitance, the relation Q = CV, dielectric materials, charging and discharging, energy formulas, and combinations of capacitors in series and parallel. Electric potential difference is needed to understand why charge and stored energy change.
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