The potential of the two plates of a capacitor are +10 V and -10 V the charge on one of the plates is 40C . The capacitance of the capacitor is :
Correct answer: A. 2 F
- A. 2 F
- B. 4 F
- C. 0.5 F
- D. 0.25 F
Explanation
The potential difference across the parallel plate capacitor is 10V- (-10)=20VCapacitance= Q/V = 40/20 = 2 FaradAs it is numerical, it can have only one possible answer.
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Capacitors store electric charge and energy in an electric field between conductors. Work includes capacitance, the relation Q = CV, dielectric materials, charging and discharging, energy formulas, and combinations of capacitors in series and parallel. Electric potential difference is needed to understand why charge and stored energy change.
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