Two capacitors of capacitance 2µF each are connected in series to a power supply of 6 volt. The voltage across each capacitor is :

Explanation

When capacitors are connected in series, the total capacitance (C_total) is given by the reciprocal of the sum of the reciprocals of the individual capacitances (C1, C2, C3, ...): 1/C_total = 1/C1 + 1/C2 + 1/C3 + ... In this case, we have two capacitors of 2µF each connected in series. Plugging in the values, we get: 1/C_total = 1/2µF + 1/2µF Simplifying the expression: 1/C_total = 2/2µF 1/C_total = 1/µF C_total = µF So the total capacitance is 1µF. Now, the voltage across each capacitor in a series circuit is the same. Therefore, the voltage across each capacitor in this case is 6 volts.