Free Chemistry of Hydrocarbons MCQs with Answers
1,091 Chemistry of Hydrocarbons MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
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- A. their carbon to hydrogen bonds are strong and almost non polar, offering nothing for a nucleophile or electrophile to attack
- B. they contain a double bond
- C. they are ionic compounds
- D. they have very high molar masses
Explanation: Carbon and hydrogen have similar electronegativities, so the bonds carry almost no dipole and there is no region of high or low electron…
Correct answer: their carbon to hydrogen bonds are strong and almost non polar, offering nothing for a nucleophile or electrophile to attack- A. sp
- B. sp2
- C. sp3
- D. unhybridised p
Explanation: Four sigma bonds require four equivalent orbitals, so one s and three p orbitals mix to give four sp3 hybrids pointing to the corners of a…
Correct answer: sp3- A. nucleophilic substitution
- B. electrophilic addition
- C. free radical substitution
- D. elimination
Explanation: Ultraviolet light splits the chlorine molecule homolytically into two radicals, which then abstract hydrogen from methane and set up a…
Correct answer: free radical substitution- A. the reaction of a chlorine radical with methane
- B. the combination of two methyl radicals
- C. the reaction of a methyl radical with chlorine
- D. the homolytic splitting of a chlorine molecule into two chlorine radicals by ultraviolet light
Explanation: Initiation is the step that creates radicals where there were none, and only the chlorine to chlorine bond is weak enough to be broken by…
Correct answer: the homolytic splitting of a chlorine molecule into two chlorine radicals by ultraviolet light- A. Free radical substitution
- B. Electrophilic addition
- C. Nucleophilic substitution
- D. Electrophilic substitution
Explanation: The exposed pi electrons of the double bond attract electrophiles, which add across the bond and convert an unsaturated compound into a…
Correct answer: Electrophilic addition- A. sodium metal
- B. silver nitrate solution
- C. bromine water, which is decolourised by the alkene
- D. limewater
Explanation: The orange colour of bromine water disappears as bromine adds across the double bond to form a colourless dibromo compound, and an alkane…
Correct answer: bromine water, which is decolourised by the alkene- A. 1-bromopropane
- B. 2-bromopropane
- C. 1,2-dibromopropane
- D. propan-2-ol
Explanation: The hydrogen adds to the carbon that already carries more hydrogens, so the bromine ends up on the middle carbon.
Correct answer: 2-bromopropane- A. sp3 and 109.5 degrees
- B. sp and 180 degrees
- C. sp2 and 120 degrees
- D. sp2 and 109.5 degrees
Explanation: Each carbon forms three sigma bonds using sp2 hybrids arranged in a plane at 120 degrees, and the remaining unhybridised p orbitals…
Correct answer: sp2 and 120 degrees- A. one sigma and two pi bonds between the carbon atoms, with sp hybridisation
- B. two sigma bonds between the carbon atoms
- C. only sigma bonds
- D. three pi bonds between the carbon atoms
Explanation: A triple bond is always one sigma bond plus two pi bonds, formed from two unhybridised p orbitals on each sp hybridised carbon, and the…
Correct answer: one sigma and two pi bonds between the carbon atoms, with sp hybridisation- A. calcium carbonate
- B. calcium oxide
- C. calcium hydroxide
- D. calcium carbide
Explanation: Calcium carbide reacts vigorously with water to give ethyne and calcium hydroxide, which was once used in carbide lamps and is still the…
Correct answer: calcium carbide11. Terminal alkynes such as ethyne react with ammoniacal silver nitrate to give a precipitate because
- A. the triple bond adds silver
- B. the hydrogen attached to the triply bonded carbon is weakly acidic and is replaced by silver
- C. silver catalyses polymerisation
- D. alkynes are strong bases
Explanation: The sp hybridised carbon holds its bonding electrons closer, so the attached hydrogen is slightly acidic and can be replaced by a metal to…
Correct answer: the hydrogen attached to the triply bonded carbon is weakly acidic and is replaced by silver- A. the molecular formula C6H6
- B. the ring shape of the molecule
- C. why benzene resists addition reactions and has all its carbon to carbon bonds of equal length
- D. why benzene contains only carbon and hydrogen
Explanation: Alternating single and double bonds would predict two different bond lengths and the ready addition reactions of an alkene, but experiment…
Correct answer: why benzene resists addition reactions and has all its carbon to carbon bonds of equal length- A. preserves the stable delocalised pi system
- B. produces a smaller molecule
- C. requires no catalyst
- D. is always exothermic
Explanation: Addition would destroy the aromatic sextet and lose the large resonance stabilisation, whereas replacing a hydrogen leaves the delocalised…
Correct answer: preserves the stable delocalised pi system- A. dilute nitric acid alone at room temperature
- B. a mixture of concentrated nitric and concentrated sulphuric acids at about 50 to 60 degrees Celsius
- C. sodium nitrate solution
- D. nitrogen dioxide gas in sunlight
Explanation: Sulphuric acid protonates nitric acid so that it loses water and generates the nitronium ion, which is the actual electrophile attacking…
Correct answer: a mixture of concentrated nitric and concentrated sulphuric acids at about 50 to 60 degrees Celsius- A. CnH2n
- B. CnH2n-2
- C. CnH2n+2
- D. CnH2n+1
Explanation: Every carbon in a saturated open chain carries the maximum hydrogen, giving two per carbon plus two extra for the ends of the chain, so…
Correct answer: CnH2n+2- A. the covalent bonds within the molecules become stronger
- B. the molecules become more polar
- C. hydrogen bonding develops between longer chains
- D. the larger surface area increases the dispersion forces between molecules
Explanation: Longer chains touch each other over a greater area, so the temporary induced dipole attractions between molecules add up to more, and more…
Correct answer: the larger surface area increases the dispersion forces between molecules- A. produce shorter, more useful alkanes and alkenes for fuel and plastics
- B. remove sulphur from crude oil
- C. convert alkenes into alkanes
- D. increase the molar mass of the products
Explanation: Fractional distillation yields more of the heavy fractions than the market wants and too little petrol, so cracking breaks the long chains…
Correct answer: produce shorter, more useful alkanes and alkenes for fuel and plastics- A. ethane
- B. ethanoic acid
- C. ethanol
- D. ethanal
Explanation: Ethene adds sulphuric acid to give ethyl hydrogen sulphate, and hydrolysing that with water releases ethanol and regenerates the acid…
Correct answer: ethanol- A. dehydration
- B. hydrogenation
- C. hydrolysis
- D. halogenation
Explanation: Hydrogen adds across the double bond to give the corresponding alkane, and this is the process used to convert liquid vegetable oils into…
Correct answer: hydrogenation- A. has a pleasant smell
- B. contains only carbon and hydrogen
- C. reacts readily by addition
- D. is planar, cyclic and has a delocalised system of six pi electrons obeying Huckel's rule
Explanation: Aromaticity in the modern sense requires a planar cyclic conjugated system containing 4n plus 2 pi electrons, which for benzene means six…
Correct answer: is planar, cyclic and has a delocalised system of six pi electrons obeying Huckel's ruleChemistry of Hydrocarbons MCQs: common questions
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