The hybridisation of each carbon atom in an alkane such as ethane is

  • A. sp
  • B. sp2
  • C. sp3
  • D. unhybridised p

Explanation

Four sigma bonds require four equivalent orbitals, so one s and three p orbitals mix to give four sp3 hybrids pointing to the corners of a tetrahedron with bond angles of 109.5 degrees. Alkenes use sp2 with 120 degree angles and alkynes sp with a linear 180 degree arrangement. Counting the sigma bonds and lone pairs on an atom is the quickest way to assign hybridisation.

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