A delegation of 5 members has to be formed from 3 ladies and 5 gentlemen. In how many ways the delegation can be formed, if 2 particular ladies are always included in the delegation?
Correct answer: A. 20
- A. 20
- B. 54
- C. 42
- D. 60
Explanation
The two specified ladies are already included, so 3 more members must be chosen from the remaining 1 lady and 5 gentlemen, giving 6 people available. The number of delegations is ⁶C₃ = 20. The likely trap is 42, which does not properly account for the two fixed members.
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