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Asked in a 2004 paper

2003 * 2004 - 2001 * 2002 = _________?

Correct answer: B. 8010

  • A. 8000
  • B. 8010
  • C. 8020
  • D. 8040

Explanation

Rewrite the products as 2003 × 2004 minus 2001 × 2002. Using n(n + 1), the difference is (2003^2 + 2003) - (2001^2 + 2001) = (2003^2 - 2001^2) + 2 = (4 × 2002) + 2 = 8010. The likely mistake is 8000 from ignoring the additional 2.

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