2003 * 2004 - 2001 * 2002 = _________?
Correct answer: B. 8010
- A. 8000
- B. 8010
- C. 8020
- D. 8040
Explanation
Rewrite the products as 2003 × 2004 minus 2001 × 2002. Using n(n + 1), the difference is (2003^2 + 2003) - (2001^2 + 2001) = (2003^2 - 2001^2) + 2 = (4 × 2002) + 2 = 8010. The likely mistake is 8000 from ignoring the additional 2.
Last updated
About Sequences and Series
Sequences describe ordered terms formed by a pattern, while series represent the sum of those terms. Questions cover arithmetic and geometric sequences, their nth terms, common difference or ratio, finite sums, and applications, with the sequence itself kept distinct from the corresponding series.
Practise Algebra
269 free Algebra MCQs from Mathematics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Mathematics questions like this
Mathematics is on 67 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.