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The number of sequences in which 7 players can throw a ball, so that the youngest player may not be the last is -.

Correct answer: C. 4320

  • A. 4000
  • B. 2160
  • C. 4320
  • D. 5300

Explanation

The 7 players can throw in 7! = 5040 sequences. If the youngest is last, the other 6 can be arranged in 6! = 720 ways, so sequences in which the youngest is not last equal 5040 - 720 = 4320 sequences. The likely trap is 5040, which includes the forbidden sequences with the youngest player last.

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Sequences describe ordered terms formed by a pattern, while series represent the sum of those terms. Questions cover arithmetic and geometric sequences, their nth terms, common difference or ratio, finite sums, and applications, with the sequence itself kept distinct from the corresponding series.

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