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A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group?

Correct answer: B. 600

  • A. 300
  • B. 600
  • C. 750
  • D. 900

Explanation

The selections are ⁴C₂ = 6 ways for men, ⁶C₃ = 20 ways for women, and ⁵C₁ = 5 ways for the child. Multiplying independent choices gives 6 x 20 x 5 = 600 ways. The likely trap is 750, which comes from miscounting one of the combinations.

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