Three dice (each having six faces with each face having one number from 1 or 6) are ralled. What is the number of possible outcomes such that atleast one dice shows the number 2?
Correct answer: C. 91
- A. 36
- B. 81
- C. 91
- D. 116
Explanation
There are 6 x 6 x 6 = 216 outcomes for three dice. Outcomes with no 2 have 5 choices for each die, giving 5 x 5 x 5 = 125, so outcomes with at least one 2 are 216 - 125 = 91; 116 does not follow from the complement calculation.
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