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In how many different ways can six players be arranged in a line such that two of them, Asim and Raheem are never together?

Correct answer: D. 480

  • A. 120
  • B. 240
  • C. 360
  • D. 480

Explanation

The six players can be arranged in 6! = 720 ways. Arrangements with Asim and Raheem together treat them as one block, giving 5! x 2! = 240, so arrangements in which they are separate are 720 - 240 = 480; 360 does not correctly subtract the adjacent arrangements.

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