In how many different ways can six players be arranged in a line such that two of them, Asim and Raheem are never together?
Correct answer: D. 480
- A. 120
- B. 240
- C. 360
- D. 480
Explanation
The six players can be arranged in 6! = 720 ways. Arrangements with Asim and Raheem together treat them as one block, giving 5! x 2! = 240, so arrangements in which they are separate are 720 - 240 = 480; 360 does not correctly subtract the adjacent arrangements.
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