A two number committee comprising of one male and the female number is to be constituted out of five male and 3 females. Amongst the females, Ms. A refused to be number committee in which Mr.B is taken as the number of how many different ways can the committee be constituted?
Correct answer: C. 14
- A. 11
- B. 30
- C. 14
- D. 20
Explanation
Without the restriction, choose 1 male from 5 and 1 female from 3, giving 5 x 3 = 15 committees. If Mr B is selected, Ms A cannot be selected, so exactly 1 invalid committee is removed and 15 - 1 = 14 remain; 20 is impossible because there are only 15 unrestricted male-female pairs.
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