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A,B,C, can do a work in 8,14,16 days respectively. A does the work for the first 2 days. B continues from it and finishes 2/3rd of the remaining work. C finishes the remaining work. How many days would have taken to complete the work?

Correct answer: A. 13

  • A. 13
  • B. 11
  • C. 12
  • D. 15

Explanation

A completes 2 × 1/8 = 1/4 of the work, leaving 3/4; B then completes 2/3 × 3/4 = 1/2, leaving 1/4. B takes (1/2) ÷ (1/14) = 7 days and C takes (1/4) ÷ (1/16) = 4 days, so total time is 2 + 7 + 4 = 13 days. The likely trap is 11 days, caused by misreading B's share of the remaining work.

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Problems measure work through rates, treating each person's or machine's contribution as work completed per unit time. Questions cover combined work, efficiency, wages, alternate working schedules, pipes and cisterns, and men-days relationships, with care needed to distinguish time taken by one worker from the time required when workers act together.

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