Free Force and Motion MCQs with Answers

1,416 Force and Motion MCQs from Physics, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.

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1,416 questions · page 23 of 71

  • A. 45o
  • B. 56o
  • C. 66o
  • D. 76o

Explanation: Equating vertical rise y = (v² sin²θ)/(2g) and horizontal distance x when projectile reaches that same point leads to tan θ = 4, yielding…

Correct answer: 76o
  • A. Mass
  • B. Weight
  • C. Velocity
  • D. Momentum

Explanation: Inertia is the resistance to changes in motion and is directly quantified by mass; greater mass implies greater inertia.

Correct answer: Mass
  • A. 9.8 m/s 2
  • B. Less than 9.8 m/s2
  • C. More than 9.8 m/s 2
  • D. Speed of throw is required for answer

Explanation: Once released (no contact forces), the only acceleration is gravity (assuming vacuum/no air resistance), so acceleration equals g ≈ 9.8…

Correct answer: 9.8 m/s 2
  • A. Force
  • B. Impulse
  • C. Acceleration
  • D. Power

Explanation: Impulse J= Δp = (rate of change of momentum) × time = Favg × Δt; thus time multiplied by the rate of change of momentum equals impulse.

Correct answer: Impulse
  • A. Uniformly accelerated motion
  • B. Motion with constant velocity
  • C. Motion with constant speed
  • D. Body at rest

Explanation: A horizontal line on a displacement-time graph shows that the object is stationary (not moving because the displacement doesn't change…

Correct answer: Body at rest
  • A. kg ms-2
  • B. Ns
  • C. N s-1
  • D. Nm

Explanation: Impulse has units of momentum, i.e., N·s (Newton-second) equivalent to kg·m/s.

Correct answer: Ns
  • A. +4 kg·m/s
  • B. -4 kg·m/s
  • C. +8 kg·m/s
  • D. -8 kg.m/s

Explanation: Initial p = +4, final p = −4 (reversed direction with same magnitude), so Δp = pf − pi = (−4) − (+4) = −8 kg·m/s = −8 kg·m/s.

Correct answer: -8 kg.m/s
  • A. 2.5 s
  • B. 5.0 s
  • C. 7.5 s
  • D. 10 s

Explanation: Vertical fall time from height h: h = 1/2 g t² ⇒ t² = 2h/g = 2×490/9.8 = 100 ⇒ t = 10 s. Horizontal speed does not affect during fall time.

Correct answer: 10 s
  • A. 15° and 18°
  • B. 43° and 47°
  • C. 20° and 80°
  • D. 52° and 62°

Explanation: Ranges are equal for complementary angles θ and 90° − θ. 43° and 47° sum to 90°, hence they give the same range for identical speeds.

Correct answer: 43° and 47°
  • A. 100 m
  • B. 80 m
  • C. 60 m
  • D. 50 m

Explanation: For maximum horizontal range at 45°, range R = v²/g. Maximum height when thrown vertically with same speed v is h = v²/(2g) = R/2 = 50 m.

Correct answer: 50 m
  • A. 100 m
  • B. 200 m
  • C. 400 m
  • D. 800 m

Explanation: For projectile at 45° maximizing range, Rmax = v²/g and Hmax = v²/(4g) = Rmax/4. Thus, H = 400/4 = 100 m.

Correct answer: 100 m
  • A. 0.25 R
  • B. 0.5 R
  • C. 0.75 R
  • D. R

Explanation: The projectile's kinetic energy is minimum at the highest point of its trajectory; the highest point occurs at half the range (R/2) for…

Correct answer: 0.5 R
  • A. 1 cm/s²
  • B. 2 cm/s²
  • C. 3 cm/s²
  • D. 6 cm/s²

Explanation: From 30s to 40s, velocity rises from 20m/s to 80m/s in 10s. So, a =(80-20)/10 = 6cm/s2. Hence, the maximum acceleration is 6cm/s².

Correct answer: 6 cm/s²
  • A. Constant velocity
  • B. Velocity of a body is changing continuously
  • C. Instantaneous velocity
  • D. The body travels with constant speed up to time t1 and then stops

Explanation: Displacement increases linearly with time up to t1 (straight line → constant velocity).

Correct answer: The body travels with constant speed up to time t1 and then stops
  • A. Graph A
  • B. Graph B
  • C. Graph C
  • D. Graph D

Explanation: When a ball is thrown vertically upwards , velocity decreases linearly with time (due to constant downward acceleration g).

Correct answer: Graph D
  • A. ab
  • B. bc
  • C. cd
  • D. de

Explanation: In segment bc, the displacement doesn't change with time. That means velocity is zero, and since there's no change in velocity…

Correct answer: bc
  • A. 1/2
  • B. 1/4
  • C. 1/3
  • D. 2/3

Explanation: Step 1: understand the graph. The graph is a trapezoid showing velocity over time, with key points at t=0, v=0; t=3,v=10m/s; constant…

Correct answer: 1/4
  • A. 3.6m
  • B. 28.8m
  • C. 36.0m
  • D. 72.0m

Explanation: Step 1: Understand the given v-t graph and the question. The v-t graph shows the velocity of a lift over time.

Correct answer: 36.0m
  • A. 15 m/s
  • B. 10 m/s
  • C. 7 m/s
  • D. 5 m/s

Explanation: Step1:The problem describes a particle moving along the sides AB,BC and CD of a square with a side length of 25m at a velocity of 15ms .

Correct answer: 5 m/s
  • A. 0 m/s
  • B. 25 m/s
  • C. 5 m/s
  • D. 2 m/s

Explanation: Step 1: Understand the given v-t plot and the question. The v-t plot shows the velocity of an object over time.

Correct answer: 0 m/s