A particle moves along the sides AB, BC,CD of a square of each side 25m with velocity of 15m/s. Its average velocity is:
Correct answer: D. 5 m/s
- A. 15 m/s
- B. 10 m/s
- C. 7 m/s
- D. 5 m/s
Explanation
Step1:The problem describes a particle moving along the sides AB,BC and CD of a square with a side length of 25m at a velocity of 15ms . Step 2: Calculate the total distance traveled: The total distance = AB+BC+CD=25m+25m+25m= 75m. Step 3: Calculate the total time taken: Total time = Total distance / Velocity =75m/15ms =5s. Step 4: Determine the displacement: The displacement is the distance between the initial point A and the final point D, which is 25m. Step5: Calculate the average velocity: Average velocity= Displacement/Total time =25m/5s=5 ms-1. The best answer is (D) 5ms-1.
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