The maximum horizontal range of a projectile is 400 m. The maximum height attained by it will be:
Correct answer: A. 100 m
- A. 100 m
- B. 200 m
- C. 400 m
- D. 800 m
Explanation
For projectile at 45° maximizing range, Rmax = v²/g and Hmax = v²/(4g) = Rmax/4. Thus, H = 400/4 = 100 m.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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