A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same effort, he throws the ball vertically upwards. The maximum height attained by the ball is:
Correct answer: D. 50 m
- A. 100 m
- B. 80 m
- C. 60 m
- D. 50 m
Explanation
For maximum horizontal range at 45°, range R = v²/g. Maximum height when thrown vertically with same speed v is h = v²/(2g) = R/2 = 50 m.
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