A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same effort, he throws the ball vertically upwards. The maximum height attained by the ball is:
Correct answer: D. 50 m
- A. 100 m
- B. 80 m
- C. 60 m
- D. 50 m
Explanation
For maximum horizontal range at 45°, range R = v²/g. Maximum height when thrown vertically with same speed v is h = v²/(2g) = R/2 = 50 m.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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