All Free Mathematics MCQs with Answers
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1,551 questions · page 58 of 78
- A. ²²C₁₀
- B. ²²C₁₀ + 1
- C. ²²C₉ + ¹⁰C₁
- D. ²²C₁₀ - 1Quiz Mode Feature
Explanation: There are 22 people altogether, so selecting any 10 gives ²²C₁₀ groups.
Correct answer: ²²C₁₀ - 1Quiz Mode Feature- A. ¹²C₅ * 10
- B. ¹²C₇ * 10
- C. ¹²C₇ * ¹⁰C₅
- D. 12 * ¹⁰C₅
Explanation: The 5 seniors can be selected in ¹²C₅ ways, and independently the 5 juniors can be selected in ¹⁰C₅ ways.
Correct answer: ¹²C₇ * ¹⁰C₅- A. 300
- B. 450
- C. 600
- D. 750
Explanation: Choose the required people independently: ⁴C₃ = 4 ways for men, ⁶C₂ = 15 ways for women, and ⁵C₃ = 10 ways for children.
Correct answer: 600- A. 300
- B. 600
- C. 750
- D. 900
Explanation: The selections are ⁴C₂ = 6 ways for men, ⁶C₃ = 20 ways for women, and ⁵C₁ = 5 ways for the child.
Correct answer: 600- A. 720
- B. 1440
- C. 1860
- D. 2160
Explanation: MATERIAL has 4 vowels, A, E, I, A, which must form one block, along with the 4 consonants. These 5 objects can be arranged in 5!
Correct answer: 1440- A. 20
- B. 54
- C. 42
- D. 60
Explanation: The two specified ladies are already included, so 3 more members must be chosen from the remaining 1 lady and 5 gentlemen, giving 6 people…
Correct answer: 20- A. 4000
- B. 2160
- C. 4320
- D. 5300
Explanation: The 7 players can throw in 7! = 5040 sequences. If the youngest is last, the other 6 can be arranged in 6!
Correct answer: 4320- A. 4800
- B. 5760
- C. 2880
- D. 15000
Explanation: Treat the 5 boys as one block, giving 4 objects to arrange: the boys' block and 3 girls. These objects can be arranged in 4!
Correct answer: 2880- A. 8000
- B. 8010
- C. 8020
- D. 8040
Explanation: Rewrite the products as 2003 × 2004 minus 2001 × 2002. Using n(n + 1), the difference is (2003^2 + 2003) - (2001^2 + 2001) = (2003^2 -…
Correct answer: 8010- A. 1600
- B. 900
- C. 3600
- D. 2500Islamic Studies Quiz
Explanation: The least common multiple of 10, 12, 15 and 18 is 180 = 2² x 3² x 5. To make this a square, the factor 5 must also occur twice, so the…
Correct answer: 900- A. 143
- B. 169
- C. 260
- D. 221
Explanation: Each remainder is one less than its divisor, so the number plus 1 must be divisible by 6, 8 and 12.
Correct answer: 143- A. 5073
- B. 5016
- C. 5054
- D. 5035
Explanation: The remainders are one less than the divisors, so n + 5 must be divisible by 6, 7, 8, 9 and 10.
Correct answer: 5035- A. 210
- B. 119
- C. 126
- D. 154
Explanation: Again, every remainder is one less than its divisor, so n + 1 is divisible by 2, 3, 4, 5 and 6.
Correct answer: 119- A. 7203
- B. 2403
- C. 3603
- D. 4803
Explanation: The heap leaves remainder 3 for division by 16, 20, 25 and 45, so n - 3 must be a multiple of their least common multiple, 3600.
Correct answer: 7203- A. 9654
- B. 9666
- C. 9664
- D. 9864
Explanation: Every stated remainder is 6 less than its divisor, so n + 6 must be divisible by 10, 15, 21 and 28.
Correct answer: 9654- A. 420
- B. 515
- C. 435
- D. 518
Explanation: The conditions can be written as n + 10 divisible by 35, 25 and 15, because the remainders are 10 less than their divisors.
Correct answer: 515- A. 78
- B. 68
- C. 58
- D. None
Explanation: The value 68 gives 68 ÷ 8 a remainder of 4, 68 ÷ 12 a remainder of 8, 68 ÷ 18 a remainder of 14, and 68 ÷ 24 a remainder of 20.
Correct answer: 68- A. 1 min
- B. 2 min
- C. 3 min
- D. None
Explanation: After t minutes, the wheels make 15t, 20t and 48t revolutions. They are all back at the original position when these three quantities are…
Correct answer: 1 min- A. 9985
- B. 9960
- C. 9957
- D. 9975
Explanation: The least common multiple of 3, 4 and 5 is 60, so the required number must be a multiple of 60.
Correct answer: 9960- A. 344
- B. 355
- C. 366
- D. 377
Explanation: The least common multiple of 6, 9, 15, 20 and 24 is 360, so the number increased by 5 must be 360. Therefore, the number is 360 - 5 = 355.
Correct answer: 355