Free Chemical Equilibrium MCQs with Answers

625 Chemical Equilibrium MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.

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625 questions · page 30 of 32

  • A. No Reaction
  • B. Backward Reaction
  • C. Little Forward Reaction
  • D. Complete Reaction

Explanation: A very small value of the equilibrium constant, Kc, indicates that the forward reaction (formation of products) is **very weak** compared…

Correct answer: Little Forward Reaction
  • A. Irreversible
  • B. Unidirectional
  • C. Multidirectional
  • D. Reversible

Explanation: A reversible reaction is one in which the conversion of reactants to products and the conversion of products to reactants occur…

Correct answer: Reversible
  • A. Maximum
  • B. Minimum
  • C. Zero.
  • D. Negligible

Explanation: Kp equals Kc times RT to the Δn. Kp is the equilibrium constant. Temperature, just like in all gas laws, needs to be in Kelvin and An…

Correct answer: Zero.
  • A. Spontaneous Reactions
  • B. Exothermic Reaction
  • C. Reversible Reaction
  • D. Combustion Reaction

Explanation: A reversible reaction is a reaction in which the conversion of reactants to products and the conversion of products to reactants occur…

Correct answer: Reversible Reaction
  • A. Atoms
  • B. Molecules
  • C. Ions
  • D. Moles

Explanation: Kc and Kp have the same value when reactants and products have the same number of "moles" asKp = Kc (RT)^∆n Since ∆n = 0, RT factor is…

Correct answer: Moles
  • A. Kc
  • B. K
  • C. Kp
  • D. None of these

Explanation: The answer is C. For partial pressure equilibrium constant will always be denoted as Kp, where 'K' stands for equilibrium ratio of…

Correct answer: Kp
  • A. Removing K+ ions from the solution
  • B. Removing ClO3- ions from the solution
  • C. Adding KCl from outside
  • D. Adding NaNO3 from outside

Explanation: Explanation:Adding KCl would increase the K+ ion concentration thus shifting the equilibrium to the left due to common ion effect, thus…

Correct answer: Adding KCl from outside
  • A. Iron
  • B. Carbon
  • C. Copper
  • D. Silver

Explanation: An iron catalyst is used in the Haber process because iron is durable, cheap, and effective at catalysis.

Correct answer: Iron
  • A. N2(g) + H2(g) ⇌ 2NH(g)
  • B. 2N(g) + 3H2(g) ⇌ NH3(g)
  • C. 2N(g) + 3H2(g) ⇌ 2NH3(g)
  • D. N2(g) + 3H2(g) ⇌ 2NH3(g)

Explanation: Below is the true reaction of haber's process:N2(g) + 3H2(g) = 2NH3(g)It is a fact and should be memorized.

Correct answer: N2(g) + 3H2(g) ⇌ 2NH3(g)
  • A. Standard
  • B. Normal
  • C. Cool
  • D. Harsh

Explanation: Nitrogen gas is a molecule with a triple bond between the atoms, which makes Nitrogen unreactive under normal conditions as it takes a lot…

Correct answer: Harsh
  • A. 46%
  • B. 82%
  • C. 14%
  • D. 17%

Explanation: The Mr of Ammonia (NH3) is 14+3=17It contains ammonia in the percentage of :14/17 x 100 = 82%

Correct answer: 82%
  • A. 3N2 (g) + 3H2 (g) <=====> 2NH3 (g)
  • B. N2 (g) + H2 (g) <=====> NH3 (g)
  • C. 3N2 (g) + H2 (g) <=====> 2NH3 (g)
  • D. N2 (g) + 3H2 (g) <=====> 2NH3 (g)

Explanation: Ammonia is synthesized in a process called Haber Process by Nitrogen (N2) and Hydrogen (H2) First of all, write the chemical equation for…

Correct answer: N2 (g) + 3H2 (g) <=====> 2NH3 (g)
  • A. (CH3-COOH)= 0.333 mol.dm-3(CH3-CH2-OH) = 1.333mol.dm-3(CH3-CH2-O-CO-CH3)= 1.666 mol.dm-3(H2O)= 1.666 mol.dm-3
  • B. (CH3-COOH)= 1.333 mol.dm-3(CH3-CH2-OH) = 0.333mol.dm-3(CH3-CH2-O-CO-CH3)= 0.666 mol.dm-3(H2O)= 0.666 mol.dm-3
  • C. (CH3-COOH)= 0.666 mol.dm-3(CH3-CH2-OH) = 0.666 mol.dm-3(CH3-CH2-O-CO-CH3)= 1.333 mol.dm-3(H2O)= 1.333 mol.dm-3
  • D. (CH3-COOH)= 0.333 mol.dm-3(CH3-CH2-OH) = 0.333mol.dm-3(CH3-CH2-O-CO-CH3)= 1.333 mol.dm-3(H2O)= 1.333 mol.dm-3

Explanation: Change in concentration of of CH3COOH is 1-0.33 = 0.66 mol.dm-3Change in concentration of of CH3CH2OH is also 1-0.33 = 0.66 mol.dm-3Where…

Correct answer: (CH3-COOH)= 0.666 mol.dm-3(CH3-CH2-OH) = 0.666 mol.dm-3(CH3-CH2-O-CO-CH3)= 1.333 mol.dm-3(H2O)= 1.333 mol.dm-3
  • A. Option A
  • B. Option B
  • C. Option C
  • D. Option D

Explanation: Explanation:It is the fact. Equilibrium constant is products/reactants.

Correct answer: Option C
  • A. mol3dm-6
  • B. moldm-3
  • C. mol-3dm6
  • D. No unit

Explanation: A, B and C are incorrect since the given units aren't correct according to the equationD is correct since In equation both sides moles are…

Correct answer: No unit
  • A. N2 + 3H2--------> 2NH3
  • B. SO2 + 2O2--------> 2SO3
  • C. CO + H2O ----------> CO2 + H2
  • D. 2NO2 + O2---------> 2NO3

Explanation: There are equal moles of reactants and products therefore Kc will have no units as they get cancelled out.

Correct answer: CO + H2O ----------> CO2 + H2
  • A. H2S2O7
  • B. HSO4-
  • C. SO3
  • D. S

Explanation: In the contact process, sulfur dioxide (formed by roasting sulfur in oxygen) is reacted with oxygen to form sulfur trioxide, which is…

Correct answer: H2S2O7
  • A. Increases with temperature
  • B. Decreases with temperature
  • C. Shows exceptional behavior
  • D. Remains constant

Explanation: The solubility of most salts increases with temperature due to increased kinetic energy and greater interaction between solute and solvent…

Correct answer: Decreases with temperature
  • A. 43
  • B. 48
  • C. 0.43
  • D. 4.3

Explanation: pH=pKa+ Log NaHCO3/H2CO3 7=4.3*10^-7+ Log NaHCO3/H2CO3 Log NaHCO3/H2CO3=7 NaHCO3/H2CO3=10^7 NaHCO3=10^7* H2C03 NaHCO3=10^7*4.3^-7 NaHCO3=4.3

Correct answer: 4.3
  • A. pH = pKa + log([Acid]/[Salt])
  • B. pH = pKa - log([Salt]/[Acid])
  • C. pH = pKa + log([Salt]/[Acid])
  • D. pH = pKa - log([Acid]/[Salt])

Explanation: Henderson-Hasselbalch equation to calculate the pH of a buffer solution ispH=pka+log[salt]/[Acid]

Correct answer: pH = pKa + log([Salt]/[Acid])