Asked in ETEA MDCAT 2012 2012Moderate

Which of the following compounds on treatment with NaHCO3 will liberate CO2?

Correct answer: A. CH3COOH

  • A. CH3COOH
  • B. C2H5NH2
  • C. CH3COCH3
  • D. CH3CH2OH

Explanation

The correct answer is CH3COOH. Carboxylic acids, such as acetic acid (CH3COOH), react with sodium bicarbonate (NaHCO3) to produce carbon dioxide (CO2), water, and a sodium salt. This reaction is due to the acidic nature of carboxylic acids, which can donate a proton to the bicarbonate ion. In contrast, ethylamine (C2H5NH2), acetone (CH3COCH3), and ethanol (CH3CH2OH) do not have the acidic hydrogen necessary to react with NaHCO3 and thus do not liberate CO2.

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About Reactivity of Carboxylic Acids

Carboxylic acids show acidic behaviour because their carboxylate ions are resonance-stabilised, and electron-withdrawing groups can change their strength. Reactions include neutralisation, esterification, formation of acid chlorides and amides, reduction, decarboxylation and substitution at the acyl carbon, which differs from the reactions of phenols.

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