Select the correct order of the acids strength?

Correct answer: B. CHCl2COOH > CH2ClCOOH > CH3COOH

  • A. CH3COOH >> CHCl2COOH > CH2ClCOOH
  • B. CHCl2COOH > CH2ClCOOH > CH3COOH
  • C. CH3COOH > CHCl2COOH > CH2ClCOOH
  • D. CHCl2COOH >> CH2COOH > CH2ClCOOH

Explanation

The acidity of carboxylic acids is influenced by the presence of electron-withdrawing groups. These groups stabilize the carboxylate ion by delocalizing the negative charge via inductive effects, thereby increasing acidity. In the given options, CHCl2COOH is the strongest acid because it has two chlorine atoms, which significantly withdraw electrons, enhancing the acid strength. CH2ClCOOH, with one chlorine, is less acidic than CHCl2COOH but more acidic than CH3COOH, which lacks electron-withdrawing groups and is thus the weakest acid. Option B correctly identifies this trend, while the other options incorrectly order the acids or introduce non-existent compounds.

This question appeared on the ETEA MDCAT 2016 paper, which you can sit online with every answer explained.

Written and checked by , M.Phil ChemistryLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About Reactivity of Carboxylic Acids

Carboxylic acids show acidic behaviour because their carboxylate ions are resonance-stabilised, and electron-withdrawing groups can change their strength. Reactions include neutralisation, esterification, formation of acid chlorides and amides, reduction, decarboxylation and substitution at the acyl carbon, which differs from the reactions of phenols.

Practise Carboxylic Acids

550 free Carboxylic Acids MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Chemistry questions like this

Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Reactivity of Carboxylic Acids questions