In SO4-2 the oxidation number of Sulphur is
Correct answer: D. +6
- A. -8
- B. +8
- C. -6
- D. +6
Explanation
The oxidation of sulphur is 6+:it is because the oxide ion has a charge of -2 making it -8 overall, for four oxide ions. x-8=-2 x=+6 As it is numerical, it can have only one possible answer.
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About Oxidation and Reduction
Oxidation involves loss of electrons, increase in oxidation number or addition of oxygen, while reduction involves electron gain, decrease in oxidation number or removal of oxygen. The topic covers oxidising and reducing agents, oxidation-number changes, redox equations and the distinction between oxidation at the anode and reduction at the cathode.
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