Free Electrochemistry MCQs with Answers

696 Electrochemistry MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

Electrochemistry describes electron transfer through oxidation and reduction, identifies oxidizing and reducing agents, and applies oxidation numbers to balance redox equations. It also covers electrode potential and the standard hydrogen electrode, which provides the reference for comparing the reduction tendencies of other electrodes.

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696 questions · page 1 of 35

  • A. loss of electrons and an increase in oxidation number
  • B. gain of electrons and a decrease in oxidation number
  • C. gain of hydrogen only
  • D. loss of oxygen only

Explanation: The modern definition is in terms of electrons, so oxidation is loss and reduction is gain, remembered as OIL RIG.

Correct answer: loss of electrons and an increase in oxidation number
Moderate
  • A. plus 2
  • B. plus 6
  • C. minus 2
  • D. plus 4

Explanation: Hydrogen contributes plus 1 each and oxygen minus 2 each, so 2 plus x minus 8 equals zero and x is plus 6.

Correct answer: plus 6
Fairly easy
  • A. the sulphate ion
  • B. copper ions
  • C. zinc
  • D. copper metal

Explanation: Zinc goes from an oxidation number of zero as the metal to plus 2 in the sulphate, so it has lost electrons and is oxidised, which also…

Correct answer: zinc
Fairly easy
  • A. loses electrons and is itself oxidised
  • B. gains electrons and is itself reduced
  • C. neither gains nor loses electrons
  • D. always contains oxygen

Explanation: An oxidising agent oxidises something else by taking its electrons, so it is itself reduced in the process, and the same reasoning in…

Correct answer: gains electrons and is itself reduced
  • A. minus 2
  • B. zero
  • C. minus 1
  • D. plus 2

Explanation: Hydrogen is plus 1, so the two oxygens must total minus 2 between them, giving minus 1 each, which is the exception to the usual rule of…

Correct answer: minus 1
  • A. a neutralisation reaction
  • B. a displacement reaction
  • C. a precipitation reaction
  • D. a disproportionation reaction

Explanation: In disproportionation one species with an intermediate oxidation state changes into two products, one at a higher and one at a lower…

Correct answer: a disproportionation reaction
  • A. the number of atoms of oxygen is the same in both
  • B. the number of electrons lost equals the number gained
  • C. the charges on both sides are zero
  • D. the coefficients are all whole numbers greater than one

Explanation: Electrons cannot appear in the final equation, so the two half equations are scaled until the electrons cancel exactly on addition, which…

Correct answer: the number of electrons lost equals the number gained
  • A. hydroxide ions
  • B. oxygen gas
  • C. water molecules to the side deficient in oxygen
  • D. hydrogen gas

Explanation: Water supplies the missing oxygen, and hydrogen ions are then added to the opposite side to balance the hydrogen introduced, which is…

Correct answer: water molecules to the side deficient in oxygen
Easy
  • A. 0.00 volts by convention
  • B. 1.00 volt
  • C. minus 1.00 volt
  • D. 0.76 volts

Explanation: No single electrode potential can be measured in isolation, so the hydrogen electrode is defined as zero and every other potential is…

Correct answer: 0.00 volts by convention
  • A. a zinc rod in zinc sulphate solution
  • B. platinised platinum foil dipping in 1 molar hydrogen ion solution
  • C. a copper rod in copper sulphate solution
  • D. a carbon rod in pure water

Explanation: Platinum is used because it is chemically inert and does not itself take part in the reaction, while the finely divided platinum black…

Correct answer: platinised platinum foil dipping in 1 molar hydrogen ion solution
Easy
  • A. cathode
  • B. salt bridge
  • C. anode
  • D. voltmeter

Explanation: The anode is by definition the electrode at which oxidation occurs and reduction occurs at the cathode, and this holds for both galvanic…

Correct answer: anode
  • A. allow electrons to pass between the two solutions
  • B. complete the circuit by allowing ions to migrate and keeping both solutions electrically neutral
  • C. prevent the cell from producing any current
  • D. act as a catalyst for the reaction

Explanation: As the cell runs, positive charge builds up in one half cell and negative charge in the other, which would stop the reaction almost…

Correct answer: complete the circuit by allowing ions to migrate and keeping both solutions electrically neutral
  • A. a strong reducing agent that is easily oxidised
  • B. a strong oxidising agent
  • C. chemically unreactive
  • D. unable to form ions

Explanation: A large negative value means the metal releases electrons readily and prefers to exist as its ion, so it is easily oxidised and therefore…

Correct answer: a strong reducing agent that is easily oxidised
  • A. plus 3
  • B. plus 12
  • C. plus 6
  • D. plus 7

Explanation: Seven oxygens contribute minus 14, and the overall charge is minus 2, so the two chromium atoms must total plus 12, giving plus 6 each.

Correct answer: plus 6
Fairly easy
  • A. lose electrons there
  • B. gain electrons and are reduced there
  • C. are attracted to the anode
  • D. react with chlorine there

Explanation: Positive sodium ions migrate to the negative cathode, each accepting one electron to become a sodium atom, which is reduction.

Correct answer: gain electrons and are reduced there
Fairly easy
  • A. a reducing agent because it gains electrons
  • B. neither an oxidising nor a reducing agent
  • C. a catalyst
  • D. an oxidising agent because it accepts electrons from sodium

Explanation: Each chlorine atom accepts one electron and falls from zero to minus 1, so chlorine is reduced and is therefore the oxidising agent, while…

Correct answer: an oxidising agent because it accepts electrons from sodium
  • A. 1 molar solution, 298 K and 1 atmosphere pressure
  • B. any concentration at 273 K
  • C. 0.1 molar solution at 373 K
  • D. pure water at room temperature

Explanation: Standard conditions fix the concentration of every solution at 1 molar, the pressure of any gas at 1 atmosphere and the temperature at 298…

Correct answer: 1 molar solution, 298 K and 1 atmosphere pressure
  • A. Zn + 2HCl gives ZnCl2 + H2
  • B. 2H2 + O2 gives 2H2O
  • C. NaOH + HCl gives NaCl + H2O
  • D. 2Mg + O2 gives 2MgO

Explanation: In neutralisation no element changes its oxidation number, since hydrogen stays at plus 1, oxygen at minus 2 and both sodium and chlorine…

Correct answer: NaOH + HCl gives NaCl + H2O
Hard
  • A. displace a metal lower in the series from its salt solution
  • B. be displaced by a metal lower in the series
  • C. never react with acids
  • D. always be a poor conductor

Explanation: A more reactive metal gives up electrons more readily, so it reduces the ions of a less reactive metal and takes their place in solution…

Correct answer: displace a metal lower in the series from its salt solution
  • A. plus 1
  • B. equal to its group number
  • C. minus 1
  • D. zero

Explanation: An uncombined element has not gained or lost any electrons, so its oxidation number is zero, and this holds for atoms such as helium and…

Correct answer: zero

Electrochemistry MCQs: common questions

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