Asked in UHS MDCAT 2017 2017Moderate

6NaOH + 3Cl2 ----> 5NaCl + NaClO3+3H2OIn the above disproportion reaction, the oxidation state of chlorine is changed from zero to _ and _.

Correct answer: C. -1, +5

  • A. -1, +1
  • B. -1, +3
  • C. -1, +5
  • D. +1, +5

Explanation

In NaCl, Na has an oxidation state of +1 so Cl is -1 and in NaClO3, Na is +1 and O is -6 while Cl is an unknown x. According to the calculation1+x-6 = 0x= +5 so Cl in NaClO3 is +5.

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About Oxidation and Reduction

Oxidation involves loss of electrons, increase in oxidation number or addition of oxygen, while reduction involves electron gain, decrease in oxidation number or removal of oxygen. The topic covers oxidising and reducing agents, oxidation-number changes, redox equations and the distinction between oxidation at the anode and reduction at the cathode.

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