In NO3- the oxidation number of N is:
Correct answer: A. 5+
- A. 5+
- B. 2+
- C. 3+
- D. 3-
Explanation
NO3N = xO = - 2x + (-2) × 3 = - 1x + (- 6) = - 1x - 6 = - 1x = - 1 + 6x = 5
This question appeared on the UHS MDCAT 2017 paper, which you can sit online with every answer explained.
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About Oxidation and Reduction
Oxidation involves loss of electrons, increase in oxidation number or addition of oxygen, while reduction involves electron gain, decrease in oxidation number or removal of oxygen. The topic covers oxidising and reducing agents, oxidation-number changes, redox equations and the distinction between oxidation at the anode and reduction at the cathode.
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