Sulphur has oxidation state of:
Correct answer: D. Both A and B
- A. ±2
- B. +4 and +6
- C. None of these
- D. Both A and B
Explanation
In H₂SO₄, the oxidation number of S is +6.In H₂SO₃, the oxidation number of S is +4.In Na₂S₂O₃, the oxidation number of S is +2.
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About Oxidation and Reduction
Oxidation involves loss of electrons, increase in oxidation number or addition of oxygen, while reduction involves electron gain, decrease in oxidation number or removal of oxygen. The topic covers oxidising and reducing agents, oxidation-number changes, redox equations and the distinction between oxidation at the anode and reduction at the cathode.
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