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Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case?

Correct answer: A. 16

  • A. 16
  • B. 17
  • C. 18
  • D. 19

Explanation

A divisor that leaves remainder 3 must divide 19 - 3 = 16, 83 - 3 = 80 and 67 - 3 = 64. Their greatest common factor is H.C.F.(16,80,64) = 16, so the required number is 16. The likely mistake is 17, which does not divide all three adjusted values.

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