A drink vendor has 80 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required?
Correct answer: B. 37
- A. 35
- B. 37
- C. 42
- D. 30
Explanation
The largest equal can size is the H.C.F. of 80, 144 and 368: H.C.F.(80,144,368) = 16 litres. The numbers of cans are 80/16 = 5, 144/16 = 9 and 368/16 = 23, so the total is 5 + 9 + 23 = 37 cans. The likely mistake is 42, from using a smaller can size instead of the greatest possible common size.
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