Free Electronics MCQs with Answers
660 Electronics MCQs from Physics, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
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Read the Electronics notesFree MDCAT chapter notes with key terms660 questions · page 16 of 33
- A. 1.21
- B. 0.6
- C. 0.482
- D. 0.9
Explanation: The values should be MEMORISEDHalf Wave = 1.21Full Wave = 0.482
Correct answer: 0.482- A. Lower half cycle
- B. Upper half cycle
- C. Both cycles
- D. None of them
Explanation: While turning AC voltage into DC voltage , full wave rectifier turns both cycles into positive cycles .
Correct answer: Both cycles- A. 80.60%
- B. 40.60%
- C. 70%
- D. 50%
Explanation: It is a fact that maximum efficiency of a full wave rectifier is 80.60%.
Correct answer: 80.60%- A. Clamper
- B. Clipper
- C. Diode clamp
- D. Limiter
Explanation: A clamper is an electronic circuit that fixes either the positive or the negative peak excursions of a signal to a defined value by…
Correct answer: Clamper- A. 10√ 2
- B. 10/√ 2
- C. 10/π
- D. 10π
Explanation: Through our knowledge, we know the peak voltage is fed with a sinusoidal signal without a filter which is 10V.
Correct answer: 10/π- A. 0.532
- B. 0.637
- C. 0.759
- D. 0.437
Explanation: The average DC voltage across the load is 0.637 Vmax.Because the current flowing through the load is uni-directional, so the voltage…
Correct answer: 0.637- A. Reversed biased
- B. Forward biased
- C. Potential barrier
- D. None of these
Explanation: Option A is correct since,during the negative cycle of the wave, the diode is reverse biased and does not allow that negative half to…
Correct answer: Reversed biased- A. Clamper
- B. Clipper
- C. Clamper circuit with negative bias
- D. Clamper circuit with positive bias
Explanation: Option B is correct since a clipper works to remove either the positive or negative half cycles of the input voltage.
Correct answer: Clipper309. A full wave rectifier is operating from 50 Hz mains. The fundamental frequency of ripple will be:
- A. 100 Hz
- B. 25 Hz
- C. 50 Hz
- D. 200 Hz
Explanation: Option A is correct since the rate of flow of charge is current.Option B is incorrect since the rate of flow of momentum is force.Option C…
Correct answer: 100 Hz- A. 1
- B. 2
- C. 3
- D. 4
Explanation: A center tap rectifier uses 2 diodes and a center-tapped transformer to convert AC voltage to DC voltage.
Correct answer: 2- A. 10√2
- B. 20/√2
- C. 20/π
- D. 20π
Explanation: The DC component of the output voltage of a full wave rectifier is equal to the peak voltage divided by pi.
Correct answer: 20/π- A. Full wave
- B. Half wave
- C. Both a) and b)
- D. None of them
Explanation: A bridge rectifier is a type of full-wave rectifier. A full-wave rectifier is a circuit that converts the entire input waveform into a DC…
Correct answer: Full wave313. A half wave rectifier is operating from 50 Hz mains. The fundamental frequency of ripple will be:
- A. 100 Hz
- B. 25 Hz
- C. 200Hz
- D. 50 Hz
Explanation: The fundamental frequency of the ripple produced by a half-wave rectifier is equal to the frequency of the AC mains, which is 50 Hz in…
Correct answer: 50 Hz- A. Half wave
- B. Full wave
- C. Bridge
- D. All of the above
Explanation: Full wave rectifiers use a wheatstone bridge arrangement to rectify the signal.
Correct answer: Bridge- A. Full wave
- B. Half wave
- C. Both A&B
- D. None of them
Explanation: In a full wave rectifier, the ripple factor is less than the half wave rectifier.
Correct answer: Full wave- A. tan-1(VD/V)
- B. sin-1(VD/V)
- C. cos-1(VD/V)
- D. cos(VD/V)
Explanation: The diode doesn't conducts when VD ≥VI . Hence θ = sin-1(VD/V).
Correct answer: sin-1(VD/V)- A. 10V
- B. 10.3V
- C. 10.7V
- D. 9.3V
Explanation: Remember that The RMS value of DC output will always be less than a.c input 10 v. Here only D option is less than 10 v hence it is correct.
Correct answer: 9.3V- A. 0.532 Vmax
- B. 0.637Vmax
- C. 0. 759Vmax
- D. 0.437Vmax
Explanation: Option B is correct since the current flowing through the load is unidirectional, so the voltage developed across the load is also…
Correct answer: 0.637Vmax- A. 1.06 %
- B. 2.06%
- C. 3.18%
- D. 4.28%
Explanation: Option C is correct since the best explanation is :w Δt ~ √(2Vr/Vp) = √(2 X 2/100) = 0.2 rad or 3.18% of the cycle
Correct answer: 3.18%- A. it needs much smaller transformer for the same output
- B. No center tap required
- C. Less PIV rating per diode
- D. All of the above
Explanation: Option D is correct since all the above-mentioned points are advantages of a bridge rectifier.
Correct answer: All of the above