Consider a peak rectifier fed by a 60-Hz sinusoid having a peak value Vp = 100 V. Let the load resistance R = 10 kn. Calculate the fraction of the cycle during which the diode is conducting.
Correct answer: C. 3.18%
- A. 1.06 %
- B. 2.06%
- C. 3.18%
- D. 4.28%
Explanation
Option C is correct since the best explanation is :w Δt ~ √(2Vr/Vp) = √(2 X 2/100) = 0.2 rad or 3.18% of the cycle
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