Free Electric Field MCQs with Answers
33 Electric Field MCQs from Physics, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
An electric field is the force experienced per unit positive test charge, with the field of a point charge given by E = kQ/r² and directed away from positive charges or toward negative charges. Questions involve field lines, superposition and force on a charge, while electric field must be distinguished from electric potential.
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33 questions · page 2 of 2
- A. 100 J
- B. 50 J
- C. 150 J
- D. 200 J
Explanation: The work done on a charge in an electric field can be calculated using the formula:Work = Charge × Electric Field × DistanceIn this case…
Correct answer: 100 J- A. An electric field.
- B. A magnetic field.
- C. Both magnetic and electric fields.
- D. Neither magnetic nor electric fields.
Explanation: An electric charge produces an electric field around it, and when the electric charge is in motion it causes a change in position of the…
Correct answer: Both magnetic and electric fields.- A. Controls the number of waves
- B. Controls the brightness of the spot formed
- C. Accelerates electrons
- D. Has positive potential with respect to the cathode
Explanation: The correct answer is B: The grid in a cathode ray oscilloscope controls the brightness of the spot formed on the screen.
Correct answer: Controls the brightness of the spot formed24. The magnitude of an electric field between two separated plates can be calculated by the relation:
- A. ΔV = Ed
- B. ΔV = E/d
- C. ΔV = E/qo
- D. E = d/ΔV
Explanation: The correct answer is Option A: ΔV = Ed. This formula is used to calculate the magnitude of the electric field (E) between two parallel…
Correct answer: ΔV = Ed- A. NmC-1
- B. Nm-2C-2
- C. Nm2C-1
- D. Nm2C-2
Explanation: Electric flux is defined as the product of the electric field and the area through which the field lines pass.
Correct answer: Nm2C-1- A. Electric field
- B. Electric flux
- C. Electric intensity
- D. Gravitational field
Explanation: SHOULD be B)A: An electric field is defined as any region around a charge in which an electric test charge would experience an electric…
Correct answer: Electric flux- A. maximum
- B. minimum
- C. Zero
- D. positive as well as negative
Explanation: The surface has an equal number of positive and negative charges, so the net charge will be zero.
Correct answer: Zero- A. Gravitational
- B. Electric field
- C. Magnetic field
- D. All the above
Explanation: A conservative field is a type of vector field in physics where the work done by a force in moving an object from one point to another is…
Correct answer: All the above- A. Its size decreases
- B. Its size increases
- C. No change
- D. None of the above
Explanation: When a soap bubble is charged, either positively or negatively, the like charges spread over its surface due to electrostatic forces.
Correct answer: Its size increases- A. X had a greater charge than Y
- B. Y had a greater charge than X
- C. Parallel but opposite
- D. Parallel, opposite and folded spirally.
Explanation: The correct answer is that X had a greater charge than Y. This conclusion is drawn from the observation that after the electric field was…
Correct answer: X had a greater charge than Y- A. Every where
- B. Only at the center of shell
- C. Only inside the shell
- D. Only one side of the shell
Explanation: Gauss's Law shows that the electric field everywhere inside a spherical shell of uniform charge density is 0.
Correct answer: Only inside the shell- A. Energy/farad
- B. Energy/ coulomb
- C. Energy/ volume
- D. Energy/volt
Explanation: The dimensions of the expression is M L-1 T-2 , which are also the dimensions of Energy/Volume½ 𝜺 0E^2𝜺i s the permittivity of free…
Correct answer: Energy/ volume- A. Negative and uniform over the surface of the sphere
- B. Zero
- C. Negative and at the point on the sphere closest to the point charge
- D. Negative and distributed non-uniformly over the enitre surface of the sphere
Explanation: If a positive point charge is placed outside a neutral conducting sphere, the net charge on the sphere will still be neutral.
Correct answer: Zero