Drops X and Y, of the same oil, remained stationary in air in the same electric field. After the field was switched off, X fell more quickly than Y. which deduction can be made?

Explanation

The correct answer is that X had a greater charge than Y. This conclusion is drawn from the observation that after the electric field was switched off, drop X fell more quickly than drop Y. The behavior of the drops in the electric field indicates that while the field was active, the electrostatic forces acting on each drop were balanced by the drag forces. Since X fell faster once the field was removed, it suggests that X must have had a greater charge to maintain equilibrium under the influence of the electric field. This indicates that the weight of the drops, which is proportional to the cube of their radii, was not sufficient to counteract the charge-induced forces on drop Y. Thus, drop X's greater charge allowed it to fall more rapidly once the electric field was no longer present.Other options are incorrect because they either contradict the observed behavior of the drops or are irrelevant to the relationship between the charges and the motion of the drops in the electric field.