Asked in PMC Practice Test 10 (2021) 2021

A charge of 2 C placed in electric field of 10 N/C what will be the work done in moving charge a distance of 5. How much work is done?

Correct answer: A. 100 J

  • A. 100 J
  • B. 50 J
  • C. 150 J
  • D. 200 J

Explanation

The work done on a charge in an electric field can be calculated using the formula:Work = Charge × Electric Field × DistanceIn this case, the charge is 2 C, the electric field is 10 N/C, and the distance is 5 m. Plugging in these values into the formula:Work = 2 C × 10 N/C × 5 m= 100 N·m= 100 JTherefore, the amount of work done on the charge is 100 J. Hence, the correct answer is A) 100 J.

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About Electric Field

An electric field is the force experienced per unit positive test charge, with the field of a point charge given by E = kQ/r² and directed away from positive charges or toward negative charges. Questions involve field lines, superposition and force on a charge, while electric field must be distinguished from electric potential.

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