All Free Physics MCQs with Answers

• A. Potential energy
• B. Electric field intensity
• C. Electric potential difference
• D. Electron-volt

Explanation: The correct answer is Electric field intensity. The electric field intensity is defined as the negative gradient of electric potential…

• A. Separation of the plates
• B. Separation and area of the plates
• C. Permittivity of the medium; separation of the plates
• D. Permittivity of the medium; separation and area of the plates

Explanation: The correct answer is Option A: Separation of the plates. The electric field strength between parallel conducting plates can be calculated…

• A. N/C
• B. V/m
• C. J/C.m
• D. All of the above

Explanation: The units of the electric field in the SI system are newtons per coulomb (N/C), or volts per meter (V/m); in terms of the SI base units…

• A. Volt/metre
• B. Newton/coulomb
• C. Joule/Coulomb.metre
• D. volt.metre

Explanation: The electric field intensity is defined as the force experienced by a positive test charge divided by the magnitude of the charge.

• A. Electric field
• B. Electric flux
• C. Electric intensity
• D. Gravitational field

Explanation: SHOULD be B)A: An electric field is defined as any region around a charge in which an electric test charge would experience an electric…

• A. maximum
• B. minimum
• C. Zero
• D. positive as well as negative

Explanation: The surface has an equal number of positive and negative charges, so the net charge will be zero.

• A. Gravitational
• B. Electric field
• C. Magnetic field
• D. All the above

Explanation: A conservative field is a type of vector field in physics where the work done by a force in moving an object from one point to another is…

• A. Its size decreases
• B. Its size increases
• C. No change
• D. None of the above

Explanation: When a soap bubble is charged, either positively or negatively, the like charges spread over its surface due to electrostatic forces.

• A. X had a greater charge than Y
• B. Y had a greater charge than X
• C. Parallel but opposite
• D. Parallel, opposite and folded spirally.

Explanation: The correct answer is that X had a greater charge than Y. This conclusion is drawn from the observation that after the electric field was…

• A. Every where
• B. Only at the center of shell
• C. Only inside the shell
• D. Only one side of the shell

Explanation: Gauss's Law shows that the electric field everywhere inside a spherical shell of uniform charge density is 0.

• A. Energy/farad
• B. Energy/ coulomb
• C. Energy/ volume
• D. Energy/volt

Explanation: The dimensions of the expression is M L-1 T-2 , which are also the dimensions of Energy/Volume½ 𝜺 0E^2𝜺i s the permittivity of free…

• A. Negative and uniform over the surface of the sphere
• B. Zero
• C. Negative and at the point on the sphere closest to the point charge
• D. Negative and distributed non-uniformly over the enitre surface of the sphere

Explanation: If a positive point charge is placed outside a neutral conducting sphere, the net charge on the sphere will still be neutral.

• A. 9.6 × 10^-19J
• B. 1.6 ×10^-19 J
• C. 3.2 ×10^-19 J
• D. 6.9 × 10^-19 J

Explanation: K.E = (1.6 ×10^-19) × (C×V) As K.E = (1.6×10^-19) (2×3) = 9.6 × 10^-19 JA.9.6 × 10^-19 J: This is the correct answer, obtained by using…

• A. 1.6 × 10^-18J
• B. 1.6 × 10^-17J
• C. 100J
• D. 100 electron volt

Explanation: Kinetic Energy = Work done = Q x V = 1.6×10−19×100=1.6×10−17 Joules. This option is correct as seen from the following relation.

• A. Each coulomb of charge from the battery supplies 9.0J of electrical energy to the whole circuit
• B. The battery supplies 9.0J to an external circuit for each coulomb of charge
• C. The potential difference across any component connected to the battery will be 9.0V
• D. There will always be 9.0V across the battery terminals

Explanation: The correct answer is Option A. A battery marked as 9.0V means it provides 9.0 joules of energy per coulomb of charge.

• A. 40 eV
• B. 40 KeV
• C. 40 MeV
• D. Zero

Explanation: A K.E is equal to EPE i.e qAV so 2e x 20V= 40 eVAs it is numerical, it can have only one possible answer.

• A. Decrease in temperature
• B. Increase in current
• C. Increase in temperature
• D. Decrease in current

Explanation: In a pure semiconductor, the resistance decreases with an increase in temperature.

• A. Large number of freely mobile electrons
• B. A large number of bound electrons
• C. A small number of free electrons
• D. A small number of bound electrons

Explanation: Metals are good conductors of electricity because they contain a large number of freely mobile electrons.

• A. Normal temperature
• B. Critical temperature
• C. Absolute temperature
• D. Curie temperature

Explanation: The temperature at which the resistance of a conductor approaches zero is called the critical temperature.

• A. Increases with light
• B. Decreases with light
• C. Decreases with darkness
• D. None of the above

Explanation: The correct answer is that the resistance of a Light Dependent Resistor (LDR) decreases with an increase in light intensity.