All Free Civil Engineering MCQs with Answers
Every Civil Engineering question in the bank, across all chapters, each with the correct answer and a written explanation. Free and unlimited, with no account needed.
631 questions · page 18 of 32
- A. CH
- B. ML
- C. CL
- D. MH
Explanation: The liquid limit is below 50 percent, so the soil has low plasticity. Its plasticity index lies above the A-line, indicating clay rather…
Correct answer: CL- A. i/γw
- B. iγsat
- C. γw/i
- D. iγw
Explanation: The seepage force per unit volume is the hydraulic gradient multiplied by the unit weight of water, expressed as iγw.
Correct answer: iγw- A. Clean sands and gravels
- B. Fine silts with very low permeability
- C. Highly compressible clays
- D. Organic soils with high water content
Explanation: Clean sands and gravels permit water to pass at a rate that can be measured conveniently under a constant hydraulic head.
Correct answer: Clean sands and gravels344. For the same soil, increasing the compactive effort generally causes the maximum dry unit weight to:
- A. Decrease while optimum moisture rises
- B. Rise while optimum moisture falls
- C. Remain constant while saturation falls
- D. Rise while optimum moisture also rises
Explanation: Greater compactive effort usually produces a higher maximum dry unit weight and a lower optimum moisture content.
Correct answer: Rise while optimum moisture falls- A. H Cc/(1 + e0) log10(σ0'/σ0')
- B. H Cs/(1 + e0) log10((σ0' + Δσ')/σ0')
- C. H Cc/(1 + e0) log10((σ0' + Δσ')/σ0')
- D. H Cc(1 + e0) log10((σ0' + Δσ')/σ0')
Explanation: For normally consolidated clay, the virgin compression index Cc is used and the stress ratio is the final effective stress divided by the…
Correct answer: H Cc/(1 + e0) log10((σ0' + Δσ')/σ0')- A. Loose sand and very soft clay
- B. Highly organic peat deposits
- C. Uniformly saturated silt only
- D. Dense sand and stiff clay
Explanation: General shear failure develops through a well-defined failure surface and is typical of dense sands and stiff, overconsolidated clays.
Correct answer: Dense sand and stiff clay- A. The surrounding soil settles relative to the pile
- B. The pile settles faster than the surrounding soil
- C. The pile tip reaches the water table
- D. The pile is installed in dense sand
Explanation: When surrounding compressible soil settles relative to a pile, interface shear acts downward along the pile shaft.
Correct answer: The surrounding soil settles relative to the pile- A. The footing self-weight only
- B. The effective overburden pressure at foundation level
- C. The allowable bearing pressure
- D. The total settlement of the footing
Explanation: Net ultimate bearing capacity removes the pressure that existed at the foundation level before construction.
Correct answer: The effective overburden pressure at foundation level349. According to Terzaghi's effective stress principle, the effective stress in a saturated soil equals:
- A. Pore water pressure minus total stress
- B. Total stress plus pore water pressure
- C. Total stress minus pore water pressure
- D. Total stress divided by pore water pressure
Explanation: Effective stress is the portion of stress carried by the soil skeleton.
Correct answer: Total stress minus pore water pressure- A. Depends only on soil plasticity
- B. Decreases as particle size increases
- C. Remains constant for all particle sizes
- D. Increases as particle size increases
Explanation: Larger particles usually create larger and more continuous flow channels, allowing water to pass more easily.
Correct answer: Increases as particle size increases- A. Fine-grained soil
- B. Coarse sand
- C. Clean gravel
- D. Open rock joints
Explanation: Fine-grained soils transmit water slowly, so the change in water level in a standpipe can be measured over time.
Correct answer: Fine-grained soil352. For a saturated soil, the relation between water content w, void ratio e and specific gravity Gs is:
- A. w = eGs
- B. w = e/Gs
- C. w = Gs/e
- D. w = e + Gs
Explanation: In a saturated soil, the volume of water equals the volume of voids. Using the phase relationships gives w = e divided by Gs, when both w…
Correct answer: w = e/Gs- A. Chemical weathering of minerals
- B. Expulsion of water from clay
- C. Distortion of the soil mass
- D. Long-term cementation of particles
Explanation: Immediate settlement occurs mainly from elastic deformation and distortion of the soil soon after loading.
Correct answer: Distortion of the soil mass- A. Current effective stress to total stress
- B. Void ratio to degree of saturation
- C. Total stress to pore water pressure
- D. Preconsolidation pressure to current effective stress
Explanation: OCR is the preconsolidation pressure divided by the current effective vertical stress.
Correct answer: Preconsolidation pressure to current effective stress- A. Factor of safety
- B. Coefficient of permeability
- C. Degree of saturation
- D. Plasticity index
Explanation: The factor of safety provides a margin against uncertainty in soil strength, loading and construction conditions.
Correct answer: Factor of safety- A. A long retaining wall
- B. A single column with adequate spacing
- C. A group of closely spaced columns
- D. A continuous row of masonry
Explanation: An isolated footing transfers the load from one column to the supporting soil.
Correct answer: A single column with adequate spacing- A. Only soil suction
- B. Only capillary pressure
- C. End bearing and shaft friction
- D. Buoyancy and surface tension
Explanation: A pile can transfer load at its tip by end bearing and along its embedded surface by shaft friction.
Correct answer: End bearing and shaft friction- A. Vertical settlement of the specimen
- B. Pore pressure at the ground surface
- C. Water content after drying
- D. Total normal stress on the shear plane
Explanation: The direct shear test provides failure pairs of shear stress and applied normal stress.
Correct answer: Total normal stress on the shear plane- A. (w - PL) / PI
- B. (LL - w) / PI
- C. (w - LL) / PL
- D. (PI - w) / LL
Explanation: Liquidity index compares the natural water content with the plasticity range, so it is (w - PL) divided by PI.
Correct answer: (w - PL) / PI- A. Percentage of sand fraction
- B. Percentage of clay fraction
- C. Percentage of silt fraction
- D. Percentage of gravel fraction
Explanation: Clay activity is the plasticity index divided by the percentage of particles finer than 0.002 mm.
Correct answer: Percentage of clay fraction