Free s-Block and p-Block Elements MCQs with Answers
1,359 s-Block and p-Block Elements MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.
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1,359 questions · page 21 of 68
- A. Potassium and Calcium
- B. Sodium and Magnesium
- C. Cesium and Barium
- D. Lithium and Beryllium
Explanation: Because of small size and high charge density, the first member of every group differs from the rest of members of same group.
Correct answer: Lithium and Beryllium- A. Sulphur has strong vander waal forces
- B. Sulphur has weak vander waal forces
- C. Phosphorous has strong vander waals forces
- D. None of these.
Explanation: Sulfur molecules have a larger number of electrons compared to phosphorus, leading to stronger van der Waals forces, which result in a…
Correct answer: Sulphur has strong vander waal forces- A. Li
- B. Na
- C. K
- D. Rb
Explanation: When Lithium is heated in air it only forms Li2O which is a normal oxide as it contains an O2- ion.
Correct answer: Li- A. Be
- B. Cs
- C. Ca
- D. K
Explanation: Option A is correct as Beryllium is one of the 2 alkaline earth metals that does not impart colour to flame test.
Correct answer: Be- A. CaO
- B. BaO2
- C. Na2O2
- D. RbO2
Explanation: Option D is correct. In superoxides oxygen has a charge of -1/2 which is the case in option D.
Correct answer: RbO2- A. Na
- B. Mg
- C. Cs
- D. K
Explanation: The metallic character of elements increases down a group (column) in the periodic table.
Correct answer: Cs- A. Solid state
- B. Liquid state
- C. Crystalline form
- D. Condensed form
Explanation: At room temperature and atmospheric pressure, chlorine (Cl2) is a yellow-green gas, while bromine (Br2) is a reddish-brown liquid.
Correct answer: Liquid state- A. Metal of II-A group
- B. Metalloid of V-A group
- C. Non-metal of VII-A group
- D. Non-metal of V-A group
Explanation: The electronic configuration [Ne] 5s2 5p5 indicates that the unknown element has:- A noble gas core (Ne)- 2 electrons in the 5s orbital- 5…
Correct answer: Non-metal of VII-A group- A. Shielding remains constant
- B. Atomic radius remains constant
- C. Proton number increases
- D. Atomic radius increase
Explanation: Ionization energy is the energy needed to remove an electron from its atom.
Correct answer: Atomic radius increase- A. Magnesium is less electropositive than calcium.
- B. Magnesium is lower than calcium in the reactivity series
- C. The enthalpy change of hydration for Mg2+ is less exothermic than for Ca2+
- D. The solubility product for Mg(OH)2 is lower than that for Ca(OH)2
- E. The magnitude of the lattice energy of Mg(OH)2 is less than that of Ca(OH)2
Explanation: The lesser the solubility product the more likely the precipitation will be.
Correct answer: The solubility product for Mg(OH)2 is lower than that for Ca(OH)2- A. Alkali metals are at the maxima and noble gases at the minima.
- B. Noble gases are at the maxima and alkali metals at the minima.
- C. Transition elements are at the maxima.
- D. Minima and maxima do not show any regular behavior.
Explanation: The correct answer is Option B: Noble gases are at the maxima and alkali metals at the minima.
Correct answer: Noble gases are at the maxima and alkali metals at the minima.- A. Reducing power in aqueous solution is maximum for Lithium metal.
- B. electron affinity order O+<O<O-22<O-2
- C. pH of aqueous solution LiCl>BeCl2>MgCl2>AlCl3
Explanation: The correct answer is Option A. Lithium metal has the maximum reducing power in aqueous solutions due to its position at the top of the…
Correct answer: Reducing power in aqueous solution is maximum for Lithium metal.- A. Na2O, MgO, Al2O3, CuO
- B. CuO, Al2O3, MgO, Na2O
- C. Al2O3, CuO, MgO, Na2O
- D. CuO, MgO, Na2O, Al2O3
Explanation: In the periodic table, as we move from left to right across a period, the basic character of oxides decreases, while the acidic character…
Correct answer: Na2O, MgO, Al2O3, CuO- A. 23.
- B. 32.
- C. 46.
- D. 64.
Explanation: According to the law of triads, when elements are grouped into sets of three with similar properties, the atomic mass of the middle…
Correct answer: 23.- A. Be > Mg > Ca
- B. Na > K > Rb
- C. Rb > K > Na
- D. Both A and B
Explanation: The correct answer is option D: Both A and B. Ionization energy decreases as you move down a group in the periodic table due to increased…
Correct answer: Both A and B- A. K > Na > Li
- B. Be > Mg > Ca
- C. N > P > As
- D. Both (b) and (c).
Explanation: Ionization energy generally decreases as you move down a group in the periodic table because the outermost electrons are farther from the…
Correct answer: Both (b) and (c).- A. V < Ti
- B. Cl > S
- C. Rb > Cs
- D. Ne > Be
Explanation: The correct order of atomic radius for Vanadium and Titanium is V > Ti because atomic radius decreases as you move from left to right…
Correct answer: V < Ti- A. Cu >Ag >Au.
- B. Cu <Ag <Au.
- C. Cu >Ag <Au.
- D. Ag >Cu <Au.
Explanation: Atomic sizes of Ag and Au are closer to each other but nuclear charge is more on Au so ionisation potential of Au is highest.(Au :889…
Correct answer: Cu <Ag <Au.- A. Iron (Z = 26)
- B. Chromium (Z = 24)
- C. Manganese (Z = 25)
- D. Vanadium (Z = 23)
Explanation: The third ionization enthalpy is the energy required to remove the third electron from a neutral atom.
Correct answer: Manganese (Z = 25)- A. O2->F-> F>O
- B. F->O2-> F>O
- C. O2->O>F->F
- D. O2-> F- >O>F
Explanation: The order of ionic radii is determined by electron configuration and nuclear charge.
Correct answer: O2-> F- >O>F