Free s-Block and p-Block Elements MCQs with Answers

1,359 s-Block and p-Block Elements MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.

Last updated

Read the s-Block and p-Block Elements notesFree MDCAT chapter notes with key terms

1,359 questions · page 19 of 68

  • A. 2H2O + NOCl + Cl2
  • B. H2 + NOCl + 2HOCl
  • C. H2O + NOCl + 2HCl
  • D. 2H2O + NOCl + 2Cl

Explanation: The reaction of HNO3 with HCl in a 1:3 molar ratio forms aqua regia, generating water (H2O), nitrosyl chloride (NOCl), and chlorine gas…

Correct answer: 2H2O + NOCl + Cl2
  • A. Sodium carbonate
  • B. Sodium bicarbonate
  • C. Sodium hydroxide
  • D. Sodium metal

Explanation: Down's cell is a method for obtaining sodium metal by the electrolysis of molten sodium chloride.

Correct answer: Sodium metal
  • A. Na2B2O7 . 10H2O
  • B. Na2B4O7 . H2O
  • C. Na2B4O7 . 10H2O
  • D. Na2B2O5 . 10H2O

Explanation: The chemical formula of Tincal, also known as borax, is Na2B4O7 . 10H2O.

Correct answer: Na2B4O7 . 10H2O
  • A. I-A, V-A and VIII-A
  • B. I-A, IV-A and VI-A
  • C. I-A, II-A and VII-A
  • D. I-A, IV-A and VII-A

Explanation: Hydrogen is unique in its periodic behavior but shows similarities to several groups.

Correct answer: I-A, IV-A and VII-A
  • A. Because of high melting point
  • B. Because d-electrons of outer shell take part in bonding
  • C. Because s-electrons of outer shell take part in bonding
  • D. Both s and d electrons takes part in bonding

Explanation: The toughness of these metals indicates strong metallic binding. This is because, apart from s-electrons of the outermost shell, the…

Correct answer: Both s and d electrons takes part in bonding
  • A. A compound in which a metal atom or ion is covalently bonded with a group of neutral molecules or anions.
  • B. A compound that contains 2 or more than 2 different elements
  • C. A compound which has complex molecular geometry
  • D. A compound that contains a complex ion and can exist independently

Explanation: A coordination complex is the product of a Lewis acid-base reaction in which neutral molecules or anions (called ligands) bond to a…

Correct answer: A compound in which a metal atom or ion is covalently bonded with a group of neutral molecules or anions.
  • A. Outermost s orbital and p orbitals
  • B. Outermost d orbital and underlying half filled f-orbitals
  • C. Outermost p orbital and underlying half filled d-orbitals
  • D. Outermost s orbital and underlying half filled d-orbitals

Explanation: Outermost s orbitals and underlying half filled d orbitals take part in binding of transition elements.

Correct answer: Outermost s orbital and underlying half filled d-orbitals
  • A. Na
  • B. K
  • C. Mg
  • D. Al

Explanation: In general, ionisation enthalpy increases across the period (left to right) on account of the increase of effective nuclear charge while…

Correct answer: K
  • A. F
  • B. Cl
  • C. Br
  • D. I

Explanation: F has maximum non-metallic character among the given non-metals.

Correct answer: F
  • A. F, S and Li
  • B. Cl, S and Li
  • C. Cl, Se and Na
  • D. F, Se and Na

Explanation: In the periodic table, electron affinity generally increases across a period and decreases down a group.

Correct answer: Cl, S and Li
  • A. Increase in atomic mass
  • B. Increase in shielding effect of the intervening electrons
  • C. Increase in proton number
  • D. Decrease in atomic size

Explanation: Ionization energy is the energy required to remove an electron from the outermost shell of the atom.

Correct answer: Increase in shielding effect of the intervening electrons
  • A. Atomic radius
  • B. Ionization energy
  • C. Ionic radius
  • D. Hydration energy

Explanation: Polarizability usually refers to the tendency of matter, when subjected to an electric field, to acquire an electric dipole moment in…

Correct answer: Atomic radius
  • A. Down the Group
  • B. Across the Period
  • C. Along the d-block
  • D. All of these

Explanation: The covalent character 'decreases in groups' as we go from top to bottom.

Correct answer: Down the Group
  • A. Nuclear charge
  • B. Number of electrons
  • C. Atomic number
  • D. All of these

Explanation: In general, ionization energy increases across a period and decreases down a group.

Correct answer: Nuclear charge
  • A. 3.4
  • B. 4.0
  • C. 1.2
  • D. 2.6

Explanation: Of the main group elements, fluorine has the highest electronegativity (EN = 4.0), and cesium has the lowest electronegativity (EN =…

Correct answer: 4.0
  • A. Nitrogen and Phosphorus
  • B. Neon and Argon
  • C. Lithium and Sodium
  • D. Carbon and Silicon

Explanation: So in periods two and three, the highest melting point elements tend to be the metal elements with the most delocalized electrons.In…

Correct answer: Carbon and Silicon
  • A. Acidity of metal
  • B. Polarization power
  • C. Basicity of metal
  • D. None of these options is correct

Explanation: Metals in lower oxidation states form more ionic and hence more basic oxides/hydroxides,while metals in higher oxidation states form more…

Correct answer: Basicity of metal
  • A. Group 2A
  • B. Group 5A
  • C. Both A & B
  • D. None of these

Explanation: Correct option is C. Elements in group 2 of the periodic table do not have a high electron affinity.

Correct answer: Both A & B
  • A. Nuclear charge
  • B. Proton number and nuclear charge
  • C. Proton number
  • D. None of the above

Explanation: Down the group, ionization energy decreases. Even though an increase in nuclear charge should cause an increase in ionization energy, an…

Correct answer: Proton number and nuclear charge
  • A. Mg²⁺
  • B. Na
  • C. Al³⁺
  • D. Na⁺

Explanation: The size of an ion depends on two factors: its parent atomic size and the charge on the ion.

Correct answer: Al³⁺