Ionization energy decreases down the group, from top to bottom, due to:
Correct answer: B. Increase in shielding effect of the intervening electrons
- A. Increase in atomic mass
- B. Increase in shielding effect of the intervening electrons
- C. Increase in proton number
- D. Decrease in atomic size
Explanation
Ionization energy is the energy required to remove an electron from the outermost shell of the atom. The factors that affect activation energy are:An increase in proton number, as more protons cause a greater electrostatic force of attraction between the nucleus and the outermost electrons, requiring more energy to overcome. A decrease in atomic size, as the force of attraction is inversely proportional to distance so, the closer the atoms are to the nucleus, the greater would be the force of attraction, which requires greater energy to overcome.The shielding effect describes the reduction in effective nuclear force of attraction between the nucleus and outer electrons due to the repulsion exerted by the inner shells of the atom. As we go down the group, the proton number increases, which would theoretically cause ionization energy to increase, but as we go down the group, the number of shells of each atom increases, successively, resulting in a greater shielding effect which reduces the effective force of attraction between the nucleus and the valence electrons. Hence, ionization energy decreases due to an increase in shielding effect down the group, i.e. option B.Option A does not have a direct impact on ionization energy, albeit atomic mass is accompanied by atomic number, closely in most atoms.Option C is a correct observation down the group, but the ionization energy still decreases even though the atomic number increases.Option D is an incorrect statement as atomic size increases down the group.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Periodic Properties and Trends
Periodic properties arise from electron configuration and effective nuclear charge, producing trends in atomic and ionic radius, ionization energy, electron affinity, electronegativity, metallic character and reactivity. Comparisons run across periods and down groups, with attention to common exceptions. The topic also relates these trends to the behavior of s-block and p-block elements.
Practise s-Block and p-Block Elements
1,359 free s-Block and p-Block Elements MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Periodic Properties and Trends questions
Within each pair of elements F & Cl, S & Se, and Li & Na respectively, the elements that release more energy upon an electron gain are:
Which of the following has maximum non-metallic character?
Which of the following elements has the lowest ionization enthalpy?
By increasing which of the following factor polarizability increases?
Covalent character of hydrides decrease _?
The ionization energy increases from left to right in a period due to increase in?