Free Chemistry of Hydrocarbons MCQs with Answers

• A. Potassium formate
• B. Potassium succinate
• C. Potassium acetate
• D. Potassium fumarate

Explanation: Option B is correct since Kolbe's electrolysis of potassium succinate gives CO2 and C2H4.

• A. HBr.
• B. HCL.
• C. Br2..
• D. None of these.

Explanation: When ethene reacts with bromine, the pi bond between the two carbon atoms is broken and the bromine molecule is added across the double…

• A. Br2/H2O.
• B. Dilute alkaline KMnO4.
• C. ZnCl2/HCl.
• D. Br2/CCl4.

Explanation: Baeyer's reagent is a solution of potassium permanganate (KMnO4) in sodium hydroxide (NaOH) used to test for the presence of unsaturation…

• A. HCl
• B. H2SO4/H2O
• C. HBr
• D. All of these options are correct

Explanation: Option C is correct since Markovnikov's rule states that with the addition of a protic acid HX to an asymmetric alkene, the acid hydrogen…

• A. Polyvinyl polymer
• B. Polyvinyl Acetylene
• C. Neoprene
• D. Chloroprene

Explanation: When vinyl acetylene (also known as 1-butyne) reacts with HCl (hydrochloric acid), it undergoes a chemical reaction known as an addition…

• A. Dilute KMnO4
• B. Acidified K2Cr2O7
• C. Acidified CuCl2
• D. Pyridine

Explanation: Alkenes are readily oxidised by cold, dilute, aqueous solution of potassium permanganate (Baeyer's reagent) to give vicinal glycols.

• A. Alkanes
• B. Alkynes
• C. Carbonyl
• D. Alkenes

Explanation: The functional group of alkenes is the presence of a double bond between two carbon atoms.

• A. Dehydration
• B. Ozonolysis
• C. Markovnikov's addition
• D. Oxidation with KMnO4

Explanation: The types of products obtained for ozonolysis can be used to determine the position of the double bond in compounds.

• A. Ethane
• B. Ethene
• C. Ethyne
• D. Methane

Explanation: Option A is incorrect as Alkanes have the highest bond length (of about 1.54 Angstrom).

• A. Ethene
• B. Ethane
• C. Ethyne
• D. Methane

Explanation: The bond length for a given pair of elements is a function of number and types of orbital overlaps.

• A. Polyvinyl polymer
• B. Polyvinyl Acetylene
• C. Neoprene
• D. Chloroprene

Explanation: The reaction of vinyl acetylene with HCl produces chloroprene. Chloroprene is a synthetic rubber that is used in a variety of…

• A. 2500°C
• B. 2600°C
• C. 2700°C
• D. 2800 °C

Explanation: When lime is heated with coke at about 2800°C in an electric furnace, calcium carbide is produced, which on hydrolysis yields acetylene.

• A. Ethylene
• B. Acetylene
• C. Acetone
• D. Ethene

Explanation: The first member of the Alkyne series is Ethyne which is also known as Acetylene in the common naming, having the formula C2H2.

• A. Red
• B. White
• C. Brown
• D. Pinkish

Explanation: Silver, in the form of Ag+, despite being a transition element, forms colourless compounds.

• A. Methane
• B. Ethane
• C. Propane
• D. Acetylene

Explanation: Carbide of alkaline earth metals are decomposed by water to form acetylene (C2H2). E.g: CaC2+ 2H2O ------ Ca(OH)2+ C2H2

• A. Benzene
• B. 1,3,5-cyclohexatriene
• C. Hexene
• D. Butane

Explanation: This option is correct since polymer is formed by combination of monomers.At 873 K when acetylene is passed through a red hot iron tube…

• A. Ozonolysis
• B. Hydroxylation
• C. Acetylide formation
• D. Kolbe's electrolysis

Explanation: Acetylene (C2H2) possesses two hydrogen atoms bonded to carbon atoms in its structure that exhibit acidic properties.

• A. 1
• B. 3
• C. 4
• D. 2

Explanation: Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation.

• A. Benzene
• B. Ethane
• C. Ethene
• D. Ethyne

Explanation: Ethyne, also known as acetylene, is the most reactive among the given options due to its triple bond between the carbon atoms.

• A. Baeyer reagent
• B. Lucas Test
• C. Decolorization of Br2 in CCl4
• D. Orange red colour with CH4/AlCl3

Explanation: Option D is correct.When aromatic hydrocarbons are treated with chloroform and aluminum chloride, orange to red colours are obtained.