Which of the following gives Markovnikov's product with Propene?
Correct answer: C. HBr
- A. HCl
- B. H2SO4/H2O
- C. HBr
- D. All of these options are correct
Explanation
Option C is correct since Markovnikov's rule states that with the addition of a protic acid HX to an asymmetric alkene, the acid hydrogen (H) gets attached to the carbon with more hydrogen substituents, and the halide (X) group gets attached to the carbon with more alkyl substituents. In this question, propene is an asymmetric alkene, and options A and C are examples of protic acids. Option B shows a diprotic acid.
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About Alkenes
Alkenes are unsaturated hydrocarbons containing a carbon-carbon double bond with sigma and pi components and restricted rotation. Their reactions include electrophilic addition of hydrogen, halogens, hydrogen halides and water, with Markovnikov orientation, oxidation, combustion and polymerisation, while their preparation commonly involves elimination from alkyl halides or alcohols.
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