What will be the output of the following code?(Arithmetic Operator)C#include <stdio.h>int main { int number = 6; int x = 0; x = -number; printf("%d", x); return 0;}.

Explanation

The code performs the following steps:Include Header:#include <stdio.h>: This line includes the standard input/output library, which provides functions like printf for printing to the console.Main Function:int main: This is the main function where the program execution begins.Variable Initialization:int number = 6;: Declares an integer variable number and assigns it the value 6.int x = 0;: Declares another integer variable x and assigns it the value 0.Negation:x = -number;: Assigns the negative of number to the variable x. The negative of 6 is -6, so x becomes -6.Print:printf("%d", x);: Prints the value of x which is -6.Return Statement:return 0;: This statement indicates successful program termination and returns a value of 0 to the operating system.