What is the output of the following C program?C#include <stdio.h>main{int a=5;int b=3;a *= b;printf("a=%d", a);}.
Correct answer: C. a=15
- A. a=3
- B. a=5
- C. a=15
- D. a=18
Explanation
Let's break down the code step by step:#include <stdio.h>: This line includes the standard input/output library, which provides functions like printf for printing to the console.main: This is the main function where the program execution begins.int a=5;: This line declares an integer variable a and initializes it with the value 5.int b=3;: This line declares another integer variable b and initializes it with the value 3.a *= b;: This line is an assignment expression. The *= operator is a shorthand for a = a * b. So, in this line, the value of b (which is 3) is multiplied by the current value of a (which is 5), and the result (15) is stored back into variable a.printf("a=%d", a);: This line prints the value of variable a to the console. Since a now holds the value 15, the output will be:a= 15
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