What is the output of the following C program?Cint number = 6;int x = 0;x = - number;printf("%d ", x);
Correct answer: C. -6
- A. 10
- B. -5
- C. -6
- D. 6
Explanation
The code performs the following steps:Variable Initialization:Declares an integer variable number and assigns it the value 6.Declares another integer variable x and assigns it the value 0.Negation:The line x = - number; assigns the negative of number to the variable x. In this case, the negative of 6 is -6, so x becomes -6.Print:The line printf("%d ", x); prints the value of x which is -6.
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