What is the output of the following code?Cint x=10°;\[y=15\]\[x=x++:\] //10, 11\[y=++y\] //16printf("%d%d", \(x.y)\).

Explanation

The correct option is (d) 11 16.Let's break down the code and analyze the errors:int x=10°: The degree symbol (°) is not a valid numeric literal in C. The code should use int x = 10; to assign the value 10 to the variable x.Missing semicolons: The lines \[y=15\] and \[x=x++:\] are missing semicolons at the end. In C, semicolons are required to terminate statements.Incorrect increment syntax: The syntax x=x++: is not a valid way to use the pre-increment operator in C. The correct way is ++x.Invalid printf format specifier: In the printf statement, %d%d is used to print two integers. However, there is no dot (.) separator between x and y. To print separate values, you need to use a comma (,) to separate them.Here's a corrected version of the code:Cint x = 10;int y = 15;x = ++x; // Pre-increment x to 11y = ++y; // Pre-increment y to 16printf("%d %d", x, y);.With these corrections, the code will output:11 16Explanation of the corrected code:int x = 10; int y = 15;: These lines declare and initialize the variables x and y.x = ++x;: This line uses the pre-increment operator to increment x by 1 before assigning its value. So, x becomes 11.y = ++y;: Similar to the previous line, y is incremented to 16 before assigning the value.printf("%d %d", x, y);: This line prints the values of x (which is 11) and y (which is 16) with a space between them.Now the code compiles and runs without errors, producing the expected output of 11 16.